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Elenna [48]
3 years ago
8

If the pointer in the figure is spun twice, find the probability that the pointer lands on red (R) both spins.

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0

The probability of the pointer lands on red(R) both spin = \frac{1}{36}

Step-by-step explanation:

Given,

The number of parts = 6

The pointer is spun twice.

To find the probability of the pointer lands on red(R) both spin.

Formula

Probability of an event = number of required outcomes ÷ the total number of outcomes.

P(A and B) = P(A)×P(B)

Now,

For one spin,

A = RED comes.

For second spin,

B = RED comes

So,

P(A) = \frac{1}{6} and P(B) =  \frac{1}{6}

Then,

P(A and B) =  \frac{1}{6} × \frac{1}{6}  = \frac{1}{36}

Hence, the probability of the pointer lands on red(R) both spin = \frac{1}{36}

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