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3 years ago

Someone please help! I’ll give brainliest!!

Mathematics

1 answer:

anyanavicka [17]3 years ago

6 0

Answer:

The answer is 65.97 yd^3

Step-by-step explanation:

The volume of a cone is: v = $\pi r^{2}\frac{h}{3}$

So, v = $\pi$ (3^2)(7/3) = 65.97345 yd^3

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Finish your work. Do it for him

VMariaS [17]

Answer:

LOL WHATS DIS HUNNNYYY

Step-by-step explanation:

8 0

3 years ago

The components of vector are ax and ay (both positive), and the angle that it makes with respect to the positive x axis is θ. Fi

Andru [333]

we can use formula

$\theta=tan^{-1}(\frac{a_y}{a_x})$

(a)

we are given

$a_x=12,a_y=12$

now, we can plug values

$\theta=tan^{-1}(\frac{12}{12})$

$\theta=tan^{-1}(1)$

$\theta=\frac{\pi}{4}rad$

(b)

we are given

$a_x=20,a_y=12$

now, we can plug values

$\theta=tan^{-1}(\frac{12}{20})$

$\theta=tan^{-1}(\frac{3}{5})$

$\theta=30.96^{\circ \:}$

(c)

we are given

$a_x=12,a_y=20$

now, we can plug values

$\theta=tan^{-1}(\frac{20}{12})$

$\theta=tan^{-1}(\frac{5}{3})$

$\theta=59.03^{\circ \:}$

6 0

3 years ago

A sample of 56 research cotton samples resulted in a sample average percentage elongation of 8.63 and a sample standard deviatio

ss7ja [257]

To solve for the confidence interval for the true average percentage elongation, we use the z statistic. The formula for confidence interval is given as:

Confidence interval = x ± z σ / sqrt (n)

where,

x = the sample mean = 8.63

σ = sample standard deviation = 0.79

n = number of samples = 56

From the standard distribution tables, the value of z at 95% confidence interval is:

z = 1.96

Therefore substituting the known values into the equation:

Confidence interval = 8.63 ± (1.96) (0.79) / sqrt (56)

Confidence interval = 8.63 ± 0.207

Confidence interval = 8.42, 8.84

5 0

3 years ago

A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated

malfutka [58]

Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = ± √9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)

7 0

3 years ago

Someone help me with #51

Orlov [11]

850 x 0.05 = 42.5
850 + 42.5 = 892.5
She earned 42.5
And 892.5 she wardens at the end of four years

8 0

3 years ago

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