Answer:
t = 13.1576 years
Step-by-step explanation:
The situation can be modeled as
P = Po.(1-r)^t
Where
t is the years transcurred
Po is the initial amount
r is the rate of change
Po = 40000
r = 10% equivalent to 0.1
Now
A quarter of the original amount
(1/4)*Po = Po.(1-r)^t
(1/4) = (0.9)^t
t = 13.1576
Please, see attached picture
To find what's bigger, you must make it common
8/15=32/50
11/20=33/60
11/20 is bigger.
The total mass of the living things on the farm is 588 kg.
<h2><u>Mass calculation</u></h2>
Since on a farm there was a cow, 2 sheep and 3 chickens, to determine what is the total mass of the 1 cow, the 2 sheep, the 3 chickens, and the 1 farmer on the farm, the following calculation must be performed :
- (6.2 x 10) + (4 x 10 x 10) + (2 x 6 x 10) + (3 x 2 x 1) = X
- 62 + 400 + 120 + 6 = X
- 588 = X
Therefore, the total mass of the living things on the farm is 588 kg.
Learn more about mass calculation in brainly.com/question/14695611
Answer:
10, 11, 12
Step-by-step explanation:
Hi there!
Let <em>x</em> be equal to the smallest integer.
Let <em>x</em>+1 and <em>x</em>+2 be equal to the consecutive integers.
We're given that:
⇒ smallest integer + 2 × middle integer = 20 + largest integer
Construct an equation:

Combine like terms:

Therefore, the smallest integer is 10.
This makes the consecutive integers 11 and 12.
I hope this helps!
Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!