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Ber [7]
3 years ago
13

What is the LCD of 1/4 and 2/3?

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0
For (4, 3) the least common multiple (LCM) is 12.

Therefore, the least common denominator (LCD) is 12.

Rewriting as equivalent fractions with the LCD:
3/12, 8/12
Hope i helped!
hjlf3 years ago
5 0
The Lowest Common Denominator of two fractions is the LCM (Lowest Common Multiples) of the two denominators.

Multiples of 4: 4, 8, 12, 16, 20
Multiples of 3: 3, 6, 9, 12, 15, 18
the first multiple they share is the LCM
In this case that would be 12

Therefore your LCD for this problem would be 12
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Jackson purchases a new car for $48,000. The car's value can be modeled by the
vekshin1

We have been given that Jackson purchases a new car for $48,000. The car's value can be modeled by the  following exponential function: y = 48000(0.76)^t where y represents the car's  value and t represents time in years. We are asked to find the decay rate as a percentage.

We know that an exponential decay function is in form y=a\cdot (1-r)^x, where,

y = Final value,

a = Initial value,

r = Decay rate in decimal form,

x = time.

Upon comparing our given function y = 48000(0.76)^t with standard decay function  y=a\cdot (1-r)^x, we can see that 1-r=0.76.

Let us solve for r.

1-1-r=0.76-1

-r=-0.24

r=0.24

Let us convert 0.24 into percentage.

0.24\times 100\%=24\%

Therefore, the decay rate is 24%.

8 0
3 years ago
What's two thirds plus six seventh?
vfiekz [6]

Answer:

32/21

Step-by-step explanation:

multiply (2/3) by (7/7) and (6/7) by (3/3). (14/21) + (18/21) is (32/21)

7 0
3 years ago
Read 2 more answers
5 less than half a number, x<br><br> please help i will give you the brainliest answer
Karo-lina-s [1.5K]

Answer: 1/2x -5

Step-by-step explanation:

Half of x , less 5. (5 less just means subtract)

5 0
3 years ago
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
Solve 9x + 3 = -33 . PLEASE HELP ME IT WILL MAKE MY DAY​
ValentinkaMS [17]

:  \implies \sf 9x + 3 =  - 33

: \implies \sf 9x =  - 33 - 3

:  \implies \sf 9x =  - 36

:  \implies \sf x =  \dfrac{ - 36}{9}  =  - 4

\therefore  \sf x =  -4

8 0
3 years ago
Read 2 more answers
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