Answer:
<h2><u>question 1</u></h2>

use product and sum method
product = -96
sum = -20
numbers needed = ( -24 , 4)
n - 24 = 0
n + 4 = 0
hence <u>n = 24 and n = -4 </u>
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<h2><u>Question 2 </u></h2>
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in the form 
= 
make use of the formula :

replace values to make 2 equations :
1.
= 3.17
2.
= -15.2
hence <u>x = 3.17 and x = -15.2</u>
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<h2><u>Question 3 </u></h2>
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<u />
use product and sum method
product = 40
sum = -14
numbers needed = (-10 , -4)
x - 10 = 0
x - 4 = 0
hence<u> x = 10 and x = 4</u>
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<h2><u>Question 4 </u></h2>
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<u />
in the form 
this becomes 
= 
can simplify by 5
= 
use product and sum method
product = -5
sum = -4
numbers needed (-5 , 1)
b-5 = 0
b + 1 = 0
hence <u>b = 5 and b = -1</u>