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ludmilkaskok [199]
3 years ago
13

I need help with number 7.

Mathematics
1 answer:
Anastaziya [24]3 years ago
7 0
Well what grade are you in cause I’m also learning some of this stuff, I actually learned it before at t(e beginning of the year
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Write 1.14 × 10 to the third power in standard notation
Inessa [10]

Since it's 10^3, move the decimal over 3 places to the right. When you do that the answer should now be 1,140.


Hope this helps!

3 0
3 years ago
Read 2 more answers
Please help me with this please.
natali 33 [55]

Answer:

f(-2) = -1

f(0) = -5

f(4) = -1

Step-by-step explanation:

The number inside of f( ) is telling you which equation to use to get the answer.

Example:

f(-2) since -2 is less than 0 you would use (x^2) - 5. So, ((-2)^2) - 5 = 4-5 = -1

f(0) since 0 is less than or equal to 0 you would use (x^2) - 5 again. So, ((0)^2) - 5 = 0-5 = -5

f(4) since 4 is grater than 3 you would use (2^(x-1)) - 9. So, (2^(4-1)) - 9 =  -1

<u><em>The Graph, try to make it as straight as possible</em></u>

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6 0
3 years ago
Find three fractions whose product is -5/24.
mariarad [96]

Answer:

Below.

Step-by-step explanation:

-5/8 * 1/3 = -5/24

-5/12 * 1/2 = -5/24

-5/6  * 1/4 = -5/24.

4 0
3 years ago
Find the root of 6x-48=0
Kisachek [45]
X=-8 final answer. hope that helps
3 0
3 years ago
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A random sample of 100 automobile owners in thestate of Virginia shows that an automobile is driven onaverage 23,500 kilometers
Anastaziya [24]

Answer:

a) 22497.7 < μ< 24502.3

b)  With 99% confidence the possible error will not exceed 1002.3

Step-by-step explanation:

Given that:

Mean (μ) = 23500 kilometers per year

Standard deviation (σ) = 3900 kilometers

Confidence level (c) = 99% = 0.99

number of samples (n) = 100

a) α = 1 - c = 1 - 0.99 = 0.01

\frac{\alpha }{2} =\frac{0.01}{2}=0.005\\ z_{\frac{\alpha }{2}}=z_{0.005}=2.57

Using normal distribution table, z_{0.005 is the z value of 1 - 0.005 = 0.995 of the area to the right which is 2.57.

The margin of error (e) is given as:

e= z_{0.005}\frac{\sigma}{\sqrt{n} }  = 2.57*\frac{3900}{\sqrt{100} } =1002.3

The 99% confidence interval = (μ - e, μ + e) = (23500 - 1002.3, 23500 + 1002.3) =  (22497.7, 24502.3)

Confidence interval = 22497.7 < μ< 24502.3

b) With 99% confidence the possible error will not exceed 1002.3

5 0
4 years ago
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