Examples of benchmarks are: 1/2, 1/4,1, 0.
These are just a few examples of benchmarks. I hope this helps. Remember benchmarks are numbers that you can use on a number line as a guideline. Mark as brainliest! :)
Answer:
The answer to your question is x² + 5/2x - 3/2 = 0
Step-by-step explanation:
Data
Quadratic equation x² + 2.5x - 1.5 = 0
Process
1.- Convert the decimals into fractions
2.5 = 25/10 = 5/2
1.5 = 15/10 = 3/2
2.- Substitution
x² + 5/2x - 3/2 = 0
3.- Conclusion
I rewrite the equation, now it is expressed in fractions. It could be solve by factoring.
Dude use the formula of height and distance to find the height of the trangle and then you can find the other side length using Pythagorus theorem
To complete the solution of - x - 8y = -1, we first need to substitute x for -15.
As so:
-(-15) - 8y = -1
15 - 8y = -1
Next, we can subtract 15 from each side to get:
15 - 15 - 8y = -1 - 15
- 8y = -16
Now, we can divide by -8 on each side to get the y by itself:
-8y / -8 = -16 / -8
y = -16 / -8
y = 2
There we go! <em>y</em> = 2 when x = -15! Hope I could help you out! Have a good one.
First thing you need to do is find your k in y = kx
So to do that insert 18 for x and 6 for y and then solve for k
y = kx
6 = k18
6/18 = k18 /18
1 / 3 = k
k = 1 /3
So now that we know what k is we can find x when y = 10. Once again insert the numbers we know. We know k = 1/3 and y = 10 and we need to find x
y = kx
10 = (1/3)x
3* 10 = 3*(1/3)x
30 = x
x = 30
