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melisa1 [442]
2 years ago
6

You have some money in your wallet. You don't know the exact amount, but you think you have 60 dollars give or take 15 dollars.

What is the difference between the largest and smallest weight of oranges in kilograms you can buy, if oranges cost 5 dollars/kg.
Mathematics
1 answer:
Karolina [17]2 years ago
6 0

Answer:

The least amount is 75 dollars.

The biggest amount is 125 dollars

Step-by-step explanation:

The absolute value function will help us determine a  range of possible values since we do not know the exact amount of money.

Defining the function.

Let x be the exact amount of money in my pocket, we can define the equation

And we know that the difference between the exact amount of money with 100 dollars must be either 25 dollars more than what we estimated, or 25 dollars less than the estimation.  So we can write:

We have a difference inside an absolute value, since we know the difference must be either +25 or -25.

Solving for x

Using the definition of absolute value we have

So if the inside of the absolute value is positive we have the first line of the piece-wise function, that is

Solving for x give us

If the inside of the absolute value is negative we have to use the second line of the piece-wise function definition

Solving for x give us

So the least amount of money in my pocket is 75 dollars and the biggest amount is 125 dollars.

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[50 points]
Marina86 [1]

Answer:

\sf \dfrac{1}{10}

Step-by-step explanation:

From the table:

  • Total number of Sophomores = 10
  • Total number of students = 37
  • Total number of Boys who are Sophomores = 1

\sf Probability \ of \ an \ event \ occurring = \dfrac{Number \ of \ ways \ it \ can \ occur}{Total \ number \ of \ possible \ outcomes}

\sf \implies P(Sophomore)=\dfrac{10}{37}

\sf \implies P(Boy \cap Sophomore)=\dfrac{1}{37}

\begin{aligned}\sf P(Boy | Sophomore) & = \sf\dfrac{P(Boy \cap Sophomore)}{P(Sophomore)}\\\\ & = \sf \dfrac{1}{37} \div \dfrac{10}{37}\\\\ & = \sf\dfrac{1}{37} \times\dfrac{37}{10}\\\\ & = \sf\dfrac{1}{10}\end{aligned}

4 0
2 years ago
Use the distributive property to rewrite each algebraic expression: Do not solve, just rewrite.
Shkiper50 [21]
<span>Use the distributive property to rewrite each algebraic expression: Do not solve, just rewrite.

1) 8(x + 7) = 8x + 56

2) 5(x - 10) = 5x - 50

3) 6(11 + x) = 66 + 6x

</span><span>Factor each expression. (Pull a common factor from each number) 

COMPLETED EXAMPLE: 27 + 12 = 3(9 + 4) → (3 is the shared factor for 27 and 12)

4) 12 + 36 = 12 (1 + 3)

5) 16 + 20 = 4 (4 + 5)

Solve each expression using the distributive property.

6) 4 x 82 = 4 (80 + 2) = 320 + 8 = 328 


7) 12 x 44 = 12 (40 + 4)  = 480 + 48 = 528

</span><span>8) Mrs. S bought 9 folders and 9 notebooks. The cost of each folder was $2.50. Each notebook cost $4. First, write an expression for the problem then find the total cost.

Expression = 9f + 9n = 9($2.50) + 9($4)

Total cost =</span>9($2.50) + 9($4) = $22.5 + $36 = $58.5
4 0
3 years ago
The solution to (d+4)^2=9 is D=
Allushta [10]

Answer:

\boxed{\sf d = -1 \ \ \ or \ \ \ d = -7}

Step-by-step explanation:

\sf Solve \:  for  \: d  \: over  \: the  \: real  \: numbers: \\  \sf \implies {(d + 4)}^{2}  = 9 \\  \\  \sf Take  \: the \:  square  \: root \:  of  \: both \:  sides: \\  \sf \implies \sqrt{ {(d + 4)}^{2} }  =  \sqrt{9}  \\  \\  \sf 9 =  {3}^{2} :   \\  \sf \implies \sqrt{ {(d + 4)}^{2} }  =  \sqrt{ {(3)}^{2} }  \\  \\  \sf \implies d + 4 =  \pm 3 \\  \\  \sf \implies d + 4 = 3 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d + 4 =  - 3 \\  \\  \sf Subtract  \: 4  \: from \:  both \:  sides:   \\ \sf \implies d + (4  - 4)= 3 - 4 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d + (4 - 4) =   - 3  - 4  \\  \\ \sf \implies d =  - 1 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d  =  - 7

4 0
2 years ago
Read 2 more answers
3.
lina2011 [118]

Answer:

B. Graph b

Step-by-step explanation:

I got this answer correct

4 0
2 years ago
Read 2 more answers
•<br> Evaluate 15 / (-3) + 5|1-21 / (-5)
katrin [286]

Answer:

20

Step-by-step explanation:

8 0
3 years ago
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