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vitfil [10]
3 years ago
9

What is 3/5 of 12? Please answer!

Mathematics
1 answer:
Andrej [43]3 years ago
6 0
Three fifths of twelve is 7.2
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(b) if the length, width, and height are increasing at a rate of 0.1 ft/sec, 0.2 ft/sec, and 0.5 ft/sec respectively, find the r
abruzzese [7]
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3 years ago
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Which shape is always an isosceles triangle?
Lady_Fox [76]
Only triangles , there isosceles if they both have two congruent sides & angles !
8 0
3 years ago
Over 6 days, jim jogged 6.5,5,3,2,3.5, and 4 miles. What is the mean distance that Jim jogged
bonufazy [111]

To get the mean distance that Jim jogged, you have to solve for the total miles he was able to jogged divided by the number of days he jogged.

6.5 miles + 5 miles + 3 miles + 2 miles + 3.5 miles + 4 miles = 24 miles / 6 days = 4

Therefore, the mean distance that Jim jogged is 4 miles.

6 0
4 years ago
In 1998, Cathy's age is equal to the sum of the four digits in the year of her birthday, then how old was Cathy in 1998?
ycow [4]

Answer:

<em>Cathy was born in 1980 and she was 18 years old in 1998</em>

Step-by-step explanation:

<u>Equations</u>

This is a special type of equations where all the unknowns must be integers and limited to a range [0,9] because they are the digits of a number.

Let's say Cathy was born in the year x formed by the ordered digits abcd. A number expressed by its digits can be calculated as

x=1000a+100b+10c+d

In 1998, Cathy's age was

1998-(1000a+100b+10c+d)

And it must be equal to the sum of the four digits

1998-(1000a+100b+10c+d)=a+b+c+d

Rearranging

1998=1001a+101b+11c+2d

We are sure a=1, b=9 because Cathy's age is limited to having been born in the same century and millennium. Thus

1998=1001+909+11c+2d

Operating

88=11c+2d

If now we try some values for c we notice there is only one possible valid combination, since c and d must be integers in the range [0,9]

c=8, d=0

Thus, Cathy was born in 1980 and she was 18 years old in 1998. Note that 1+9+8+0=18

5 0
4 years ago
The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative
madam [21]

The true statement is:

"The range of the function is all real numbers less than or equal to 9."

<h3>Which statements are true?</h3>

Here we have the quadratic function:

f(x) = -x^2 - 4x + 5

And we want to see which of the given statements are true.

The first one is:

"The domain is al real numbers less than or equal to -2"

This is false, for all quadratic functions the domain is the set of all real numbers (unless the domain is defined).

The second statement is:

" The domain of the function is all real numbers less than or equal to 9."

Also false

Third one:

" The range of the function is all real numbers less than or equal to −2"

The range of a quadratic function with a negative leading coefficient will be the set of all the values smaller than the y-value of the vertex.

In this case, the quadratic function is:

f(x) = -x^2 - 4x + 5

So the vertex is at:

x = 4/(2*-1) = -2\\

Then the y-value of the vertex is:

f(-2) = -(-2)^2 - 4*(-2) + 5 = -4 + 8 + 5 = 9

So the range is the set of all real numbers less than or equal to 9.

So the above statement is false, and the final one:

"The range of the function is all real numbers less than or equal to 9."

Is the true statement.

If you want to learn more about quadratic functions:

brainly.com/question/1214333

#SPJ1

8 0
2 years ago
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