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2 years ago

8

So I have another math question that involves the same problem and so is 7 + 7x the same as 7x+ 7 i think it is but i'm not sure

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2 answers:

ANEK [815]2 years ago

7 0

Yes I’m pretty sure it’s the same thing lol

BartSMP [9]2 years ago

6 0

Answer:

it is

Step-by-step explanation:

because it addition it doesn't matter which way you put it

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3 years ago

You rented a car on vacation to go sightseeing for a day. You had to pay $50 for the day and $.15 per mile, along with $35 for g

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The number of miles for which the car has been driven if one paid $122.50 as in the task content is; 2.5 miles.

<h3>For how many miles was the car driven?</h3>

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1 year ago

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$ </em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

<u>Formula for the coordinate of mid-point</u> : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are $(-2,-1)$ and $(1,0)$

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3 years ago

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You are attempting to make a scale drawing of your room. The actual size of your room is 12 feet

olga2289 [7]

Answer:

width = 8 inches

length = 10 inches

Step-by-step explanation:

width= 12/1.5

= 8

length = 15/1.5

= 10

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3 years ago