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Trava [24]
3 years ago
9

If the typos are randomly distributed over the 10 pages, find the probability of having a single typo on each page

Mathematics
1 answer:
ella [17]3 years ago
4 0
1/10 assuming there is are 10 typos in total
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Select the correct answer.
Semenov [28]

Answer:

B

hope it helped

4 0
2 years ago
(1 + 9.8k)(2.8) simplified
o-na [289]

Answer:

<em>2.8 + 27.44k</em>

Step-by-step explanation:

<u>Algebraic Simplification</u>

The rules of algebra can be applied in some situations to make expressions simplified or expanded, according to the specific needs of each problem.

We are given the expression:

(1 + 9.8k)(2.8)

It's a sum and a product. We cannot add the independent term with the variable term, so we can only multiply the factor and the contents of the parentheses as follows:

(2.8)1 + (2.8)9.8k

Operating:

2.8 + 27.44k

5 0
2 years ago
On three examinations, you have grades of 85, 78, and 84. There is still a final examination, which counts as one grade In order
Greeley [361]

Answer:

  • It's not possible to earn an A in the course
  • I must have a 73 or MORE to earn a B in the course

Step-by-step explanation:

The average obtained at the end of the course will be:

\frac{85+78+84+x}{4} = av

Where x is the grade obtained in the final examination and av is the final average. To obtain an A, av has to be at least 90, av≥90, and to obtain an B, av has to be at least 80, av≥80

  • Is an A in the course possible?

So, if we get 100 on the final average:

x = 100,

av = (85+78+84+100)/4 = 86,75 and  86,75∠90.

<em>Answer: No, the higher grade obtained would be 86,75.</em>

  • What grade you must have in the final to earn a B in the course

To earn a B, av≥80:

av= \frac{85+78+84+x}{4 \ }\geq  80\\ \frac{247+x}{4}\geq80   \\247+x\geq 80*4\\ x\geq 320-247\\ x\geq 73

<em>Answer: I must have a 73 or MORE to earn a B in the course</em>

6 0
3 years ago
Wrire a fraction that is less than 5/6 and has a denominator of 8
gulaghasi [49]
...0/8, 1/8, 2/8, 3/8, 4/8, 5/8
3 0
3 years ago
I neee #14 PLEASE! Thanks! &lt;3
Ksenya-84 [330]
I hope this helps you

5 0
2 years ago
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