So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
Answer:
b.10 inches
Step-by-step explanation:
Answer:
5sqrt3
Step-by-step explanation:
Using the pythagorean theorem, we have a^2+4^2=9^2
a^2 + 16 = 81
a^2 = 75.
a = sqrt75.
75 = 25*3. 25 is a perfect square, so sqrt75 = 5sqrt3
Answer:
x = 1
Step-by-step explanation:
The two angles, ∠HGI & ∠IGF, when combined, will result in ∠HGF.
Note:
m∠IGF = 135x
m∠HGI = 26x
m∠HGF = 161°
Set the equation:
m∠IGF + m∠HGI = m∠HGF
Plug in the corresponding terms to the corresponding variables:
135x + 26x = 161
Combine like terms:
(135x + 26x) = 161
161x = 161
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Divide 161 from both sides:
(161x)/161 = (161)/161
x = 1
1 is your answer.
~
x = 161/161 = 1
