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horsena [70]
3 years ago
14

Rewrite as a power 1 7/9

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
6 0

Answer:

1\frac{7}{9} =\frac{16}{9} =[\frac{4}{3}] ^{2}

Step-by-step explanation:

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Solve. please. help.
kumpel [21]

Answer:

x=5 y=3

Step-by-step explanation:

7 0
3 years ago
Find the missing length. the triangles are similar.
stich3 [128]
70 + 78 + 91 = 239
239 - 42 - 36 = 161
8 0
3 years ago
Read 2 more answers
Dean put together first boxes for 5 of his neighbors. Each box cost $1.00 and contained a plant and a $3.00 pair of gardening gl
Scorpion4ik [409]
(5 Neighbors) x (($1.00 Box) + (? Plant) + ($3.00 Gloves)) = 42.50

5 x (1 + x + 3) = 42.50

Combine in parens.

5 x (4 + x) = 42.50

Distribute.

20 + 5x = 42.50

Subtract 20 from both sides.

5x = 22.50

Divide both sides by 5.

x = 4.50

Thats the cost of each plant.

Check.

5 x (1 + 4.50 + 3)

5 x 8.50 = 42.50
3 0
3 years ago
The ratio of papayas to mangoes is 3:4 and the ratio of papaya to apple is 5:2. If there are 27 pieces of apple, hoe many mangoe
bija089 [108]
I m not sure of the answer but this is my best try

Papaya: Mango = 3:4
Papaya: Apple   = 5:2
Lets take no of papaya as x

So, 5/2 = x/27
By cross- multiplication, x= 27*5/2
                                       x= 67.5

Total number of papayas = 67.5
Lets take number of mangoes as y

So, 3/4 = 67.5/y
By cross multiplication, y= 90

Therefore, total number of mangoes are 90 mangoes.
7 0
4 years ago
Read 2 more answers
Prove that if one solution for a quadratic equation of theform x2 + bx + c = 0 is rational (where b and c are rational),then the
Elenna [48]

Answer:

The other solution of the given equation x² + bx + c = 0   is also rational number.

Step-by-step explanation:

Here, given: ax² + bx + c = 0 is a quadratic equation

Also, one solution  (r)  of equation is RATIONAL.

To show: The other solution (s)  is also RATIONAL

Now, here: as x² + bx + c = 0

Since r and s are the two given solutions, the given equation can be factorized as:

x² + bx + c =  (x -r) (x - s)

Simplifying LHS, we get:

(x -r) (x - s) = x x - r (x) - s (x) +  (r)(s)

                 =  x² + x(-r - s) +  rs

or, x² + bx + c = x² + x(-r - s) +  rs

Comparing the related terms, we get:

b =  (-r - s)    

⇒  b +  s = - r

or, s  = -r - b

Now, given : r = Rational  and the negative of a rational is also rational.

⇒  -r is also rational

Also, difference of two rational number is also rational.

⇒ -r - b is also rational

⇒ s is a RATIONAL NUMBER

Hence, the other solution of the given equation x² + bx + c = 0   is also rational number.

7 0
4 years ago
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