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mel-nik [20]
3 years ago
12

What is the value of x

Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0
<span>6−4x=−2x−4
</span>−4x+2x= −4−6
(−2x=−10)*−1
x=10/5
x=2
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Find the are of a circle with a diamtere of 8 cm. use 3.14 and round to your nearest hundredth
gregori [183]

Step-by-step explanation:

step 1. the area of a circle is A. A = (pi)r^2.

step 2. if the diameter is 8 cm then the radius is 4 cm.

step 3. A = (pi)4^2

step 4. A = 16(pi) = 50.24 cm.

8 0
3 years ago
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Write an equation of the circle with center,( −2,8) and radius <br> 4.
marta [7]
The equation of a circle is defined by:
(x-h)^2+(y-k)^2=r^2
Where (h,k) s the center and r is the radius.

We can translate the word problem into (x+2)^2+(y-8)^2=16

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6 0
3 years ago
Choose two axioms that allow 6 + (x + 5) to be written x + 11.
kap26 [50]
Associative means that you can move the parenthesis around the problem and still get the same answer. like (4+2)+3=4+(2+3) 
first & sixth are the true
4 0
3 years ago
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Estimate the following sum by clustering.<br><br> 128.2 + 129.11 + 132.5
swat32
If we round each of these numbers Then we get a good estimation 
128.2 rounds out to be 130 
129.11 rounds out to be 130
132.5 rounds out to be 130

So now we just add these rounded numbers up. 
130 + 130 + 130 = 390

So our answer is 390

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7 0
3 years ago
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Write a coordinate proof. Prove quadrilateral KLMN, having vertices K(–5, –4), L(0, 8), M(7, 4), and N(8, –4) is not a parallelo
Thepotemich [5.8K]

Answer:

From the calculation,

KL = 13

NM = √65

Hence KL ≠ NM

Therefore, the quadrilateral KLMN is not a Parallelogram.

Step-by-step explanation:

K(–5, –4), L(0, 8), M(7, 4), and N(8, –4)

Where we have vertices, (x1, y1) , (x2, y2)

We use the formula

√(x2 - x1)² + (y2 - y1)²

Side KL = K(–5, –4), L(0, 8)

√(x2 - x1)² + (y2 - y1)²

√(0 - (-5))² + (8 - (-4))²

√ 5² + 12²

√25 + 144

= √169

= 13

Side KN = K(–5, –4), N(8, –4)

√(x2 - x1)² + (y2 - y1)²

√(8 -(-5))² + (-4 - (-4))²

√13² + 0²

√169

=13

Side MN = M(7, 4), N(8, –4)

√(x2 - x1)² + (y2 - y1)²

√(8 -7)² + (-4 - 4)²

√1² + (-8)²

√1 + 64

√65

Side LM = L(0, 8), M(7, 4),

√(x2 - x1)² + (y2 - y1)²

√(7-0)² + (4 - 8)²

√(49)² +(-4)²

√ 49 + 16

√65

We were asked in the above question to prove that the quadrilateral with the given vertices is not a Parallelogram.

One of the characteristics of a Parallelogram is that the opposite sides are parallel and congruent to one another. This means that, the opposite sides are similar .

For the Quadrilateral KLMN above to be a Parallelogram, this means

KL = NM

From the above calculation,

KL = 13

NM = √65

Hence KL ≠ NM

Therefore, the quadrilateral KLMN is not a Parallelogram.

8 0
3 years ago
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