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3 years ago

Jenna has 8 pairs of jeans. Three of them are blue. What percentage of her jeans is blue?

Mathematics

2 answers:

yan [13]3 years ago

5 0

Divide 8 by 3 then convert the answer to percent form

harina [27]3 years ago

3 0

It would be 37.5% but it would be recognized as 37%.

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Romashka [77]

Step-by-step explanation:

$\frac{-x^{2}+9}{x+3} \\ \\ \frac{-(x^{2}-9)}{x+3} \\ \\ \frac{-(x-3)(x+3)}{x+3} \\ \\ -x(x-3)$

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2 years ago

What is the hypotenuse

diamong [38]

Answer:

Step-by-step explanation:

<em>c</em> is the hypotenuse. c = √a^2+b^2. To clarify, both a squared and b squared should be under the square root symbol.

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3 years ago

What is the value of x when x + 10=4

Juliette [100K]

ANSWER: -6

x+10-10 = 4-10
x=-6

7 0

3 years ago

Read 2 more answers

The fuel efficiency (in miles per gallon) of midsize minivans made by two auto companies is compared. Twenty test drivers are ra

Neporo4naja [7]

Answer:

$4.7-2.100*3.114*\sqrt{\frac{1}{10}+\frac{1}{10}}=1.775$

$4.7+2.100*3.114*\sqrt{\frac{1}{10}+\frac{1}{10}}=7.625$

So on this case the 95% confidence interval would be given by $1.775 \leq \mu_A -\mu_B \leq 7.625$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_A=57.9$ represent the sample mean A

$\bar X_B =53.2$ represent the sample mean B

n1=10 represent the sample A size

n2=10 represent the sample B size

$s_1 =3.4$ sample standard deviation for sample A

$s_2 =2.8$ sample standard deviation for sample B

$\mu_1 -\mu_2$ parameter of interest.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:

$(\bar X_A -\bar X_B) \pm t_{\alpha/2} s_p \sqrt{\frac{1}{n_A}+\frac{1}{n_B}}$ (1)

Where $s_p$ represent the standard deviation pooled given by:

$s_p =\sqrt{\frac{(n_A -1)s^2_A +(n_B -1)s^2_B}{n_A +n_B -2}}$

$s_p =\sqrt{\frac{(10 -1)(3.4)^2 +(10-1)(2.8)^2}{10 +10 -2}}=3.114$

The point of estimate for $\mu_A -\mu_B$ is just given by:

$\bar X_A -\bar X_B =57.9-53.2=4.7$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_A +n_B -2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.10$