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aleksandr82 [10.1K]
1 year ago
5

Simplifly the expression: x-3x-(-5x)

Mathematics
1 answer:
s2008m [1.1K]1 year ago
7 0

Answer:

The answer is 3x.

Step-by-step explanation:

I used a calculator

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irina [24]

Option D:

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7

Solution:

Given expression is \left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right).

<u>To find the product of the expression:</u>

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)

Multiply each term of the first term with each term of the 2nd term.

           =y^{2}\left(8 y^{2}+y+1\right) +3 y\left(8 y^{2}+y+1\right) +7\left(8 y^{2}+y+1\right)

Using the exponent rule: a^m \cdot a^n = a^{m+n}

           =\left(8 y^{4}+y^3+y^2\right) +\left(24 y^{3}+3y^2+3y\right) +\left(56 y^{2}+7y+7\right)

           =8 y^{4}+y^3+y^2+24 y^{3}+3y^2+3y+56 y^{2}+7y+7

Arrange the terms with same power.

           =8 y^{4}+y^3+24 y^{3}+y^2+3y^2+56 y^{2}+7y+3y+7

           =8 y^{4}+25 y^{3}+60 y^{2}+10y+7

Hence option D is the correct answer.

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7

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3 years ago
What are the domain and range of the function f(x) = 3X + 5?
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Answer:

Domain: x ER

Range: f(x) ER

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