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3 years ago

Julia worked on her chores from 3:15 until 4:00 how long did julia work

Mathematics

2 answers:

Dafna1 [17]3 years ago

7 0

45 minutes i m sure all you do is count up or subtract 60 from 15

seraphim [82]3 years ago

3 0

Well to get from 3:15 to 4:00 you need to add 45 min. So that's the awnser(45 min.)

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NO SCAM PLEASEEEE

damaskus [11]

The answer is 11/36

2/12 chance of rolling fours

because there are 2 sides containing a four on both dice combined and 12 sides in total.

Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.

I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.

1/6 * 1/6 = 1/36 chance to roll double of ones

And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:

1/36 * 5 = 5/36

So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:

5/36 + 2/12 =

5/36 + 6/36 =

11/36

5 0

2 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Juli2301 [7.4K]

Answer:

4/8

Step-by-step explanation:

8 is how many cookies in total and 4 is how many that needs to be distributed.

7 0

3 years ago

An experienced carpenter can frame a house twice as fast as an apprentice. Working together, it takes the carpenters 2 days. How

AleksAgata [21]

Answer:

6 days

Step-by-step explanation:

Let the time taken by Carpenter working alone = $C$ days

Then time taken by apprentice alone = Twice as that of taken by Carpenter = 2 $C$ days

Time taken working together = 2 days

Work done in one day working together = $\frac{1}{2}$

Work done in one day by Carpenter working alone = $\frac{1}{C}$

Work done in one day by apprentice working alone = $\frac{1}{2C}$

Work done in one day by Carpenter working alone + Work done in one day by Carpenter working alone = $\frac{1}{C}$ + $\frac{1}{2C}$ = Work done in one day working together = $\frac{1}{2}$

$\dfrac{1}{C}+\dfrac{1}{2C}=\dfrac{1}{2}\\\Rightarrow \dfrac{2+1}{2C}=\dfrac{1}{2}\\\Rightarrow C = 3\ days$

Time taken by Carpenter alone to complete the work = 3 days

Time taken by Apprentice alone to complete the work = 3 $\times$ 2= 6 days

4 0

3 years ago

:. Solve for w. P = 2(1 + w)

iragen [17]

answer : 1 = P/2 - 2

6 0

2 years ago

Read 2 more answers

Hodel just got her driver's license. Her parents offer her two options. 1. They'll buy her a used car that will cost her $0.50 p

Romashka-Z-Leto [24]

Answer:

The second option will cost her less than the first one.

Step-by-step explanation:

In order to solve this problem we will create two functions to represent the cost of the car in function of the miles drove by her.

For the first option we have:

$cost_1(x) = 0.5*x$

For the second option we have:

$cost_2(x) = 5000 + 0.1*x$

Since she intends to drive it for 10,000 miles per year for 6 years, then the total mileage she intends to drive her car is 60,000 miles. Applying this to the formula of each car and we have:

$cost_1(60000) = 0.5*60000 = 30000$

$cost_2(60000) = 5000 + 60000*0.1 = 11000$

The second option will cost her less than the first one.

7 0

3 years ago