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V125BC [204]
3 years ago
11

John put away 36 of 48 shirts in his closet. Don has 84 shirts. If he put away the same percent, how many shirts did Don put in

his closet?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
3 0

Answer:

63

Step-by-step explanation:

John's percentage:

36 and 48 have a common factor of 12 so divide both of them by 12.

36/12= 3 and 48/12=4 therefore

so 36/48= 3/4 which is 75% but we don't need to focus on the percent.

Don's no. of shirts:

we know Don has 84 shirts so we say

3/4 of 84= no. of shirts that Don put in his closet

84/4=21 21x3=63

Don put 63 shirts in his closet.

Hope that helped! Anymore questions just ask! :)

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Maricella solves for x in the equation 4x-2(3x-4)+4=-x+3(x+1)+1 . She begins by adding –4 + 4 on the left side of the equation a
Anni [7]

Answer:

Option 1.

Step-by-step explanation:

The given equation is

4x-2(3x-4)+4=-x+3(x+1)+1

To solve the given equation for x, first we need to use distributive property.

Using Distributive property we get

4x-2(3x)-2(-4)+4=-x+3(x)+3(1)+1

Now we need to add -2(-4)+4 on left side and 3(1)+1 on right side.

It is given that Maricella begins by adding –4 + 4 on the left side of the equation and 1 + 1 on the right side of the equation.

She was incorrect because the multiplication that takes place while distributing comes before addition and subtraction in order of operations.

Therefore, the correct option is 1.

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3 years ago
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2 years ago
During the first 14 days 2744 people visited a new store. The same number of people visited the store each day. About how many p
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Everyday about 200 people visited the store Because you would divide 2744 by 14 and get 196 and round that to 200 
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A manufacturer claims that the mean tensile strength of thread A exceeds the average tensile strength of thread B. To test his c
BaLLatris [955]

The complete part of the first sentence is;

A manufacturer claims that the average tensile strength of thread A exceeds the average tensile strength of thread B by at least 12 kilograms.

Answer:

we fail to reject the null hypothesis and conclude that the difference of the average tensile strength of thread A and thread B is less than 12

Step-by-step explanation:

We are given;

n_A = 16

n_B = 16

x'_A = 185 kg

x'_B = 178 kg

s_A = 6 kg

s_B = 9 kg

Let μ_A denote the population average tensile strength of thread A

Also, Let μ_B represent the population average tensile strength of thread B

Thus;

Null Hypothesis; H0;μ_A - μ_B ≤ 12

Alternative hypothesis;H1; μ_A - μ_B > 12

From the image attached, with a significance level of 0.05, the critical value for right tailed is 1.645. So we will reject the hypothesis is z > 1.645

Formula for z is;

z = (x'_A - x'_B - d_o)/√((s_A²/n_A) + (s_B²/n_B))

Plugging in the relevant values, we have;

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Since the z-value is less than 1.645,we fail to reject the null hypothesis and conclude that the difference of the average tensile strength of thread A and thread B is less than 12

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3 years ago
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