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wariber [46]
3 years ago
5

You need to have a password with 6 letters followed by 3 odd digits between 0 and 9

Mathematics
2 answers:
uysha [10]3 years ago
6 0

Answer:

9,945,936,000.

Step-by-step explanation:

This is the number of permutations of 6 letters from 26 multiplied by number of permutations of 3 odd digits between 0 and 9.

The total number of odd digits between 0 and 9 are 1,3,5,7,9 = 5.

So the number of choices are

26P6 * 5P3.

=  26!/(26-6)! * 5!/ 2!

= 26!/20! * 5!/2!

= 165765600 * 60

= 9945936000.

Amiraneli [1.4K]3 years ago
4 0

Answer:

Step-by-step explanation:

(26!/20!)(5!/2!)=9945936000

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Below

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Step-by-step explanation:

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\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

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