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wariber [46]
3 years ago
5

You need to have a password with 6 letters followed by 3 odd digits between 0 and 9

Mathematics
2 answers:
uysha [10]3 years ago
6 0

Answer:

9,945,936,000.

Step-by-step explanation:

This is the number of permutations of 6 letters from 26 multiplied by number of permutations of 3 odd digits between 0 and 9.

The total number of odd digits between 0 and 9 are 1,3,5,7,9 = 5.

So the number of choices are

26P6 * 5P3.

=  26!/(26-6)! * 5!/ 2!

= 26!/20! * 5!/2!

= 165765600 * 60

= 9945936000.

Amiraneli [1.4K]3 years ago
4 0

Answer:

Step-by-step explanation:

(26!/20!)(5!/2!)=9945936000

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5 0
3 years ago
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How do you solve 32 - 6x = 53?
katrin2010 [14]

\large\boxed{x=-\frac{7}{2}}

To solve for x, we need to isolate it on one side of the equation.

The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.

Subtract 32 from both sides of the equation.

\begin{aligned}32-32-6x&=53-32\\-6x&=21\end{aligned}

Divide both sides of the equation by -6.

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2 years ago
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daser333 [38]

Hi there!


In math terms, when we think of the words "Taken away", we immediately think of subtraction/subtracting. So, the symbol that you're looking for looks sort of like a dash.


- is what it looks like.


Hope this helps!

Message me if you need anything else! I'd be happy to help you! :D

6 0
3 years ago
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weqwewe [10]

If i'm mistaken; he needs to buy 3 sheets?

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mrs_skeptik [129]

Answer:

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