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vladimir1956 [14]
3 years ago
7

Pls help ps it says to show all work

Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer:

18

Step-by-step explanation:

x =27-9

=18

<h3>I hope it's helpful for you</h3>
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If point G is rotated 90 degrees counter clockwise around the origin, what is the resulting point?
Alex787 [66]

Answer: Point F

Step-by-step explanation:

the formula for rotation of 90 degrees counter-clockwise is (-y, x).

G=(-3,-2)

After 90 degrees counter-clockwise G is =(2,-3) which is equal to point F.

5 0
3 years ago
A semi-circle window can be used above a doorway or as an accent window
anzhelika [568]

A semicircle is a part of a circle, and it is referred to as half of a given circle. Thud the area of the <em>semi-circle</em> window is 982 in^{2}.

A circle is a shape that is <u>bounded</u> by a <em>curved</em> path which is referred to as the <em>circumference</em>. Some <u>parts</u> of a circle are radius, diameter, sector, arc, semi-circle, circumference, etc.

A <em>semicircle</em> is a <u>part</u> of a <u>circle</u>, and it is referred to as <em>half </em>of a given <em>circle</em>.

such that:

<em>Area</em> of a <u>circle</u> = \pi r^{2}

and

area of a <u>semicircle</u> = \frac{\pi r^{2} }{2}

where: r is the <u>radius </u>of the <u>circle</u>, and \pi is a <u>constant </u>with a value of \frac{22}{7}.

Thus from the given question, it can be inferred that;

r = \frac{50}{2}

 = 25

r = 25 in

Thus, the area of the<em> semi-circle</em> can be determined as;

area of the <em>semi-circle</em> = \frac{1}{2} * \frac{22}{7} * 25^{2}

                                      = 982.1429

area of the semi-circle = 982.14 in^{2}

The area of the <em>semi-circle</em> window is approximately 982 in^{2}.

for more clarifications on the area of a semi-circle, visit: brainly.com/question/15937849

#SPJ 1

8 0
2 years ago
What are easy ways to study for the EOG and NCFE?
vesna_86 [32]
I am an organized person, so i make a checklist of all my notes and study them in order and that helps me a lot for the EOGs

4 0
4 years ago
Find y.<br> Round to the nearest tenth.<br> Z<br> 17 ft<br> 8 ft<br> Х<br> 16 ft<br> Y
stealth61 [152]

Answer:

19.75 degrees

Step-by-step explanation:

cos \: x =  \frac{adja}{hypo}

cos \: y =  \frac{16}{17}

y = {cos}^{ - 1}   \frac{16}{17}

y = 19.75 \: degrees

6 0
3 years ago
Find all sides of a right triangle whose perimeter is equal to 60 cm and its area is equal to 150 square cm
miskamm [114]

Answer:

15cm by 20cm by 25cm

Step-by-step explanation:

Let the sides of the right angle be x, y and h

x is the breadth

y is the height

h is the hypotenuse

Perimeter = x + y + h

x + y +h  = 60

x+y = 60-h .... 1

If its area is equal to 150 square cm, then;

Area = 1/2 * base * height

Area = 1/2 *x * y

xy/2 = 150

xy = 300 ....2

According to pythagoras theorem;

x² + y² = h²

On expanding x² + y²

x² + y² = (x+y)² - 2xy

The equation becomes

(x+y)² - 2xy = h² ... 3

Substitute equation 1 and 2 into 3;

From 3;

(x+y)² - 2xy = h² ... 3

(60-h)² - 2(300) = h²

3600-120h + h² - 600 = h²

3600-120h - 600 = 0

-120h = 600-3600

-120h = -3000

h = 3000/120

h = 25cm

Recall that x+y+h = 60

x+y+25 = 60

x+y = 60 - 25

x+y = 35 ... 4

From equation 2;

xy = 300

x = 300/y ..... 5

Substitute 5 into 4;

300/y + y = 35

(300+y²)/y = 35

300+y² = 35y

y²-35y + 300 = 0

y²-20y-15y + 300 = 0

y(y-20)-15(y-20) = 0

y-20 = 0 and y - 15 =0

y = 20 and 15

since x+y = 35

x + 20 = 35

x = 35 - 20

x = 15

Hence the sides of the triangle are 15cm by 20cm by 25cm

8 0
3 years ago
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