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omeli [17]
3 years ago
15

What are easy ways to study for the EOG and NCFE?

Mathematics
1 answer:
vesna_86 [32]3 years ago
4 0
I am an organized person, so i make a checklist of all my notes and study them in order and that helps me a lot for the EOGs

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Sams bill at a restaurant is $12, and he leaves a 20% tip. What is the total bill including the tip
Setler79 [48]
The tip is $2.40 and the bill is$14.40
4 0
3 years ago
Find the value of x.<br><br> A.18<br> B.15<br> C.16<br> D.19<br><br> PLEASE HELP!!!!!
In-s [12.5K]

Answer:

x = 19

Step-by-step explanation:

123°+3x = 180°

3x = 180°-123°

3x = 57

x = 57/3

x = 19

The reason why we use 123° + 3x = 180° because both are adjacent angles. Adjacent angles add up to 180°

7 0
2 years ago
At the start of the diet keirin weighted 14 stone 13 pounds three months later he weighted 13 stone 10 pounds there are 14 pound
WINSTONCH [101]

Answer:

The amount of weight he has lost in 3 months is 1.215 stone or 1 stone 3 pounds

Step-by-step explanation:

From the above question, we are to calculate the amount of weight he has lost in three months

1 stone = 14 pounds

Let's convert all the weight lost to stone

At the start of the diet keirin weighted 14 stone 13 pounds

14 pounds = 1 stone

13 pounds = x

Cross Multiply

14x = 13

x = 13/14

x = 0.9285714286 stone

Approximately = 0.929 stone

Hence:

14 stone 13 pounds = 14 + 0.929 = 14.929 stone

Three months later he weighted 13 stone 10 pounds

14 pounds = 1 stone

10pounds = x

Cross Multiply

14x = 10

x = 10/14

x = 0.7142857143 stone

Approximately = 0.714 stone

Hence:

13 stone 10 pounds = 13 + 0.714 = 13.714 stone

The amount of weight he has lost is calculated as:

14.929 stone - 13.714 stone = 1.215 stone or 1 stone 3 pounds

5 0
2 years ago
What is the range and domain of f(x)=60-0.18x
Gnom [1K]

The domain is always the value of x, but there is no value of x shown..

3 0
3 years ago
Find the perimeter of the object <br><br> Help step by step please!
aliina [53]

Answer:

29.42 units

Step-by-step explanation:

<u>1) Find the perimeter around the semi-circle</u>

To do this, we find the circumference of the circle using the given diameter:

C=\pi d where d is the diameter

Plug in 6 as the diameter

C=\pi (6)\\C=6\pi

Divide the circumference by 2

\frac{6\pi }{2} \\= 3\pi

Therefore, the perimeter around the semi-circle is 3π units.

<u>2) Find the perimeter around the rest of the shape</u>

Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those <em>vertical</em> sides facing the right add up to 6. We also know that all of those <em>horizontal </em>sides facing up add up to 7. Please refer to the attached images.

Therefore, we add the following:

7+6+7

= 20

Therefore, the perimeter around that area of the shape is 20 units.

<u>3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape</u>

20+3\pi \\= 20+9.42\\= 29.42

Therefore, the perimeter of the shape is approximately 29.42 units.

I hope this helps!

3 0
3 years ago
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