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3 years ago

If point G is rotated 90 degrees counter clockwise around the origin, what is the resulting point?

Mathematics

1 answer:

Alex787 [66]3 years ago

5 0

Answer: Point F

Step-by-step explanation:

the formula for rotation of 90 degrees counter-clockwise is (-y, x).

G=(-3,-2)

After 90 degrees counter-clockwise G is =(2,-3) which is equal to point F.

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Use the number line to model why -7+3=-4

Nataly_w [17]

-7 -6 -5 -4 -3 -2 -1 0 1 2 3

There is a number line

Start on -7 and move forward 3
-6 -5 -4
Therefore yoy are left on -4

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3 years ago

Y= 10x - 32 what is the x and y value of this equation

Marrrta [24]

Answer:

$y=10x-32 \\ \\ x=\frac{y}{10}+3.2$

Step-by-step explanation:

$y=10x-32$

Because that's the equation given.

To solve for x, isolate the variable and then divide by the coefficient.

$y=10x-32 \\ \\ 10x=y+32 \\ \\ x=\frac{y}{10}+\frac{32}{10} \\ \\ x=\frac{y}{10}+3.2$

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3 years ago

Find the equation in standard form of the line parallel to y=-1/5x+7 and passing through the point (-10,-3)

Softa [21]

Answer:

the desired equation is y = (-1/5)x - 5.

Step-by-step explanation:

Parallel lines have the same slope. Here that slope is -1/5.

Let's use the slope-intercept form of the equation of a straight line:

y = mx + b

We know this new line passes through (-10, -3). Substitute -3 for y in y = mx + b, as well as -10 for x and -1/5 for m:

-3 = (-1/5)(-10) + b and solve for b:

-3 = 2 + b. Then b = -5, and the desired equation is y = (-1/5)x - 5.

8 0

3 years ago

What is (2,7) rotated 90% clockwise

ohaa [14]

Answer:

The required point is, (7, -2)

Step-by-step explanation:

The straight line passing through (0,0) and (2,7) is,

y = $(\frac {7 -0}{2-0}) \times x$

⇒ y = 3.5x --------------(1)

Now, the straight line perpendicular to this line and passing through (0, 0) is

y = $(\frac {-1}{3.5}) \times x$

⇒ 7y + 2x = 0 -------------(2)

Let, (h,k) be the required point.

then, it is on the line 7y + 2x = 0

⇒7k + 2h = 0

⇒k = $(\frac {-2}{7}) \times h$ ------------(3)

Again, distance from (0,0) of (h, k) is same as that of (2,7)

⇒ $h^{2} + k^{2} = 4 + 49 = 53$

⇒ $h^{2} \times (\frac {53}{49})$ = 53 [putting the value of k from (3)]

⇒ $h^{2}$ = 49

⇒h = 7 [since, (h,k) is in 4th quadrant, so,h >0]

So, k = -2 [putting the value of h in (3)]

So, the required point is, (7, -2)

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3 years ago

Help.. hello this is geometry right triangles test thanks

Sergeu [11.5K]

Answer:

r2 + h2 = t2

Step-by-step explanation:

pythagorean theorem : a2 + b2 = c2

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3 years ago