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Answer: the diameter of circle b is also less than circle a ?
We are given a right triangle that has angles of 45°-45°-90°. This would
indicate that the triangle is an isosceles type. We can use some
trigonemetric functions to solve for the other legs. We do as follows:
sin 45 = p / 10
p = 5√2
cos 45 = q /10
q = 5√2
<span>Hope this answers the question. Have a nice day.</span>
The perimeter of a semicircle consists of two parts. (the curve and bottom)
That curve is half the distance around the circle, since it's been split in half.
The distance around a circle, the circumfrence, is equal to 2πr, where r is the radius of that circle. In this case, the circumfrence of the entire circle would be 16π. and so that curve would have a length of just 8π.
Using 3.14 for π, 8π = 8×3.14 = 25.12.
As for the flat part, that is the diameter (distance across) our circle.
The radius is the distance from the center of a circle to its edge, and always has half the length of the diameter. (you can break the diameter down into two radii)
If our radius is 8 meters, our diameter (the flat part of that semicircle) must be 16.
Now we add up the two parts of the perimeter...25.12 + 16 = 41.12.
Answer:
7groups
Step-by-step explanation:
15+6/3=7groups
