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3 years ago

Let f(x)=2x-3 and g(x)=x+4. Find f(g(x)) and g(f(x)). f(g(x)) =

Mathematics

1 answer:

White raven [17]3 years ago

6 0

Answer:

f(g(x)) = =2(-x^2+5)-3

=-2x^2+10-3

=-2x^2+7

Sorry, I'm not sure about g(f(x)).

Step-by-step explanation:

f(g(x))=f(-x^2+5)=2x-3

=2(-x^2+5)-3

=-2x^2+10-3

=-2x^2+7

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Maurice's family put a pool into their backyard. It is rectangular in shape and its dimension are 20 feet by 10 feet by 10 feet.

s344n2d4d5 [400]

Answer:

C. $150

Step-by-step explanation:

6 0

3 years ago

There are 132 counters in a bag. The ratio of green counters to purple

DedPeter [7]

9514 1404 393

Answer:

77 purple counters

Step-by-step explanation:

There are a total of 5+7=12 ratio units, so each stands for 132/12 = 11 counters. The 7 ratio units representing the purple counters stand for ...

11 × 7 = 77 purple counters

4 0

3 years ago

What is the area of this partial circle with a radius of 14 inch

AveGali [126]

Step-by-step explanation:

Since this circle is partial we will divide the area of the whole circle by 2

the area of a circle is expressed by $\pi r^2$ so insert 14 for the radius.

$14^2\pi$

$196\pi$

divide the area by 2

$98\pi=307.876$

Hope that helps :)

6 0

3 years ago

The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m

larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words $=\frac{13!}{4\times 2!\times 3!}=64,864,800$

When M's are together . considering 2 M's as one

therefore there are $\frac{12!}{3\times 2!\times 3!}=9,979,200$

No of ways $=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600$

(b)No of ways such that M's are separated by at least 2 letters

at least 2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

$=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

$=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

$=45738000$

7 0

3 years ago

The functions q and r are defined as follows.<br> HELP PLEASE

dusya [7]

Answer:

-22

Step-by-step explanation:

First do r(3) by replacing x with 3 in r:

2*3^2 + 2 = 2*9 + 2 = 18 + 2 = 20

Then replace r(3) with 20 to do q(20):

-20-2 = -22

7 0

3 years ago