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cricket20 [7]
4 years ago
15

Line segment YV of rectangle YVWX measures 24 units. What is the length of line segment YX? 8 units units 12 units units

Mathematics
2 answers:
motikmotik4 years ago
6 0
I assume there is a missing piece of information here, either the area or the perimeter should be given.
I'll just tell you how to solve this type of problems and you can apply using the information in your question.

If YV is the width of the rectangle, then YX will be its length.

Now, if the area is known:
area of triangle = width x length = YV x YX
YX = area / 24

If the perimeter is known:
perimeter of rectangle = 2 (length + width)
perimeter = 2 (YV + YX)
YX = (perimeter / 2) - 24
sleet_krkn [62]4 years ago
5 0

Answer:

its 8/3  B

Step-by-step explanation:

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A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi
Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

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