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Mark brainliest please
Answer:
4 ( m⁶ - 4p¹⁰ )
Step-by-step explanation:
4m⁶ = 4 * m⁶
16p¹⁰= 4 * 4 * p¹⁰
Common factor = 4
4m⁶ - 16p¹⁰ = 4 ( m⁶ - 4p¹⁰ )
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
Answer:
Step-by-step explanation:
12.66-n=7.64
12.66-7.64=n
5.02=n