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3 years ago

Give the answer the areaaaaaa

Mathematics

1 answer:

GalinKa [24]3 years ago

8 0

Answer:

Step-by-step explanation:

The figure shown is a trapezoid

Area of a trapezoid = 1/2(bottom base length + top base length) × height

Bottom base length = 7 units

Top base length = 1 unit

Height = 4 units

So area = 1/2 ( 7 + 1 ) × 4

==> add 7 and 1

Area = 1/2 (8) × 4

==> multiply 1/2 and 8

Area = 4 × 4

==> multiply 4 and 4

Area = 16

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What happens to the volume of a cylinder when the height is doubled

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Answer:

If the radius of a cylinder is doubled and height is halved, the volume will be doubled. If the radius of a cylinder is doubled and height is halved, the volume will be doubled.

Step-by-step explanation:

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Find the slope and y-intercept of the line in the graph.

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3 years ago

Henry has a box in the shape of a

anyanavicka [17]

The amount of wrapping paper that he needs to cover the pyramid will be 105 square inches.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

Henry has a box in the shape of a square pyramid.

He wants to wrap the box with paper.

If the base has side lengths of 5 in. and the lateral height is 8 in.

Then the amount of the wrapping paper that he needs to cover the pyramid will be

$\rm Area = 4 \times \dfrac{1}{2} \times 5 \times 8 + 5 \times 5\\\\\\Area = 80 + 25\\\\\\Area = 105 \ in^2$

Thus, the amount of wrapping paper that he needs to cover the pyramid will be 105 square inches.

More about the geometry link is given below.

brainly.com/question/7558603

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3 years ago

Your calculator is showing a result of 248.592.<br> What is this to the nearest whole number?

Elan Coil [88]

The nearest whole is 200.600

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3 years ago

Read 2 more answers

There are three modes of transporting material from Ontario to Florida, namely, by land, sea, or air. Also land transportation m

Semenov [28]

Answer:

0.057

0.6140

0.3158

0.0701

Step-by-step explanation:

Given that:

Let :

P(L) = Number transported by land = half = 50% = 0.5

P(S) = number transported by sea = 30% = 0.3

P(A) = Number transported by air = (100 - (50 + 30))% = 20% = 0.2

P(H) = highway transport = 40% of land transport = 0.4 * 0.5 = 0.2

P(R) = Rail shipment =(100- 40)% = 60% of land transport = 0.6 * 0.5 = 0.3

Percentage of damaged cargo :

Let probability of damage = P(d)

P(d | H) = 0.1

P(d | R) = 0.05

P(d | S) = 0.06

P(d | A) = 0.02

1) What percentage of all cargoes may be expected to be damaged

[P(d | H)*p(H)] + [P(d | R)*p(R)] + [P(d | S)*p(S)] + [P(d | A)*p(A)]

(0.1*0.2) + (0.05*0.3) + (0.06*0.3) + (0.02*0.2) = 0.057

(2) If a damaged cargo is received, what is the probability that it was shipped by ;

land?

((0.1*0.2) + (0.05*0.3)) / (0.1*0.2) + (0.05*0.3) + (0.06*0.3) + (0.02*0.2)

= 0.035 / 0.057

= 0.6140

By sea?

(0.06 * 0.3) / 0.057

= 0.3158

By air?

(0.02 * 0.2) / 0.057

= 0.0701

7 0

3 years ago