Yes it dosent matter how many zeros are after the 2
Answer:
See below
Step-by-step explanation:
Y component of velocity is 70 sin 30°
y position = 3 + 70 sin 30° * t - 1/2 a t^2
when the ball hits the ground y = 0
0 = 3 + 70 sin 30° t - 1/2 (32.2)t^2
- 16.1 t^2 + 35t + 3 = 0
Use Quadratic Formula to find t = <u>2.26 seconds</u>
Horizontal component of initial velocity
70 cos 30° distance horizontal = 70 cos 30° * t
= 70 cos 30° (2.26) =<u> 137.0 ft</u>
Answer:
The third one from left to right
Step-by-step explanation:
Just check that when x = 11
y= ![-\sqrt[3]{11-3}+4=-2+4=2](https://tex.z-dn.net/?f=-%5Csqrt%5B3%5D%7B11-3%7D%2B4%3D-2%2B4%3D2)
So the graph passes through the point (11,2)
the answer is x+y≤2
The sum of x and y is greater than or equal to 2
