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3 years ago

You invest $300 in an account for 8 years that earns 2% simple interest. How much Interest will you have?

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

8 0

Answer: $48

Step-by-step explanation:

Principal×Rate×Time

$300×2/100×8yrs

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choose the point-slope form of the equation below that represents the line that passes through the points (-3,2) and (2,1)

UkoKoshka [18]

The answer should be: (2 - 1) = m(-3 - 2)

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3 years ago

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10 6 4 15 6 8 6 15 4 find the median range of the data if necessary round to the nearest tenth

Lelu [443]

Reorder from least to greatest.

4, 4, 6, 6, 6, 8, 10, 15, 15

Median is the middle number.

This would be 6.

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3 years ago

Evaluate each expression when x=2, y=-5 and z=3 <br> xy-z

gulaghasi [49]

when x=2, y=-5 and z=3

xy-z

2(-5)-3

-10-3

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3 years ago

Can you define f(0, 0) = c for some c that extends f(x, y) to be continuous at (0, 0)? If so, for what value of c? If not, expla

Ahat [919]

(i) Yes. Simplify $f(x,y)$ .

$\displaystyle \frac{x^2 - x^2y^2 + y^2}{x^2 + y^2} = 1 - \frac{x^2y^2}{x^2 + y^2}$

Now compute the limit by converting to polar coordinates.

$\displaystyle \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} = \lim_{r\to0} \frac{r^4 \cos^2(\theta) \sin^2(\theta)}{r^2} = 0$

This tells us

$\displaystyle \lim_{(x,y)\to(0,0)} f(x,y) = 1$

so we can define $f(0,0)=1$ to make the function continuous at the origin.

Alternatively, we have

$\dfrac{x^2y^2}{x^2+y^2} \le \dfrac{x^4 + 2x^2y^2 + y^4}{x^2 + y^2} = \dfrac{(x^2+y^2)^2}{x^2+y^2} = x^2 + y^2$

and

$\dfrac{x^2y^2}{x^2+y^2} \ge 0 \ge -x^2 - y^2$

Now,

$\displaystyle \lim_{(x,y)\to(0,0)} -(x^2+y^2) = 0$

$\displaystyle \lim_{(x,y)\to(0,0)} (x^2+y^2) = 0$

so by the squeeze theorem,

$\displaystyle 0 \le \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} \le 0 \implies \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} = 0$

and $f(x,y)$ approaches 1 as we approach the origin.

(ii) No. Expand the fraction.

$\displaystyle \frac{x^2 + y^3}{xy} = \frac xy + \frac{y^2}x$

$f(0,y)$ and $f(x,0)$ are undefined, so there is no way to make $f(x,y)$ continuous at (0, 0).

(iii) No. Similarly,

$\dfrac{x^2 + y}y = \dfrac{x^2}y + 1$

is undefined when $y=0$ .

5 0

1 year ago

How do you solve 7(7a-9)>84

timama [110]

7(7a-9)>84

first multiple out to get rid of the parentheses

49a - 63 > 84

add 63 to both sides

49a > 147

Divide by 49 and flip the sign because when you divide a inequality you have to flip the sign

a < 3

6 0

3 years ago