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nikitadnepr [17]

3 years ago

7

Solve by factoring. m^2+8m+7=0 A. 8,7 B. -7,1 C. -7,-1 D. 7,1

1 answer:

REY [17]3 years ago

5 0

The answer is c, -1 or -7

Hope this helped :)

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BRAINLIEST ASAP! PLEASE HELP ME :)

WITCHER [35]

Answer:

sin⁴x - sin²x

sin²x(sin²x - 1)

(1 - cos²x)(1 - cos²x - 1)

(1 - cos²x)(-cos²x)

-cos²x + cos⁴x

cos⁴x - cos²x

4 0

3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago

Please help fassssst

Zarrin [17]

Answer:

$\dfrac{9}{2}$

Step-by-step explanation:

You can do this using the quadratic equation:

$x =\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

Let's first setup our expression:

4x² + 12x = 135

the quadratic formula is:

ax² + bx + c = 0

4x² + 12x - 135 = 0

Then:

a = 4

b = 12

c = -135

Now we plug in our coefficients and solve:

$x =\dfrac{-12\pm\sqrt{12^{2}-4(4)(-135)}}{2(4)}$

We solve for both to determine the positive one:

$x =\dfrac{-12+ \sqrt{12^{2}-4(4)(-135)}}{2(4)}$ $x =\dfrac{-12- \sqrt{12^{2}-4(4)(-135)}}{2(4)}$

$x =\dfrac{-12+ \sqrt{144+2160}}{8}$ $x =\dfrac{-12- \sqrt{144+2160}}{8}$

$x =\dfrac{-12+ \sqrt{2304}}{8}$ $x =\dfrac{-12- \sqrt{2304}}{8}$

$x =\dfrac{-12+ 48}{8}$ $x =\dfrac{-12- 48}{8}$

$x =\dfrac{36}{8} = \dfrac{9}{2}$ $x =\dfrac{-60}{8} = \dfrac{-15}{2}$

So if you are looking for a positive solution, just take the positive one as x.

8 0

3 years ago

The radius of a circle is 6 inches. What is the circle's circumference?<br> Use 3.14 for .

Vikentia [17]

Answer:

37.68 inches

Step-by-step explanation:

The equation for the circumference of the circle is:

$C=2\pi r$

We can substitute 6 in for "r" and 3.14 for "π":

$C=2(3.14)(6\ in)\\C=12\ in(3.14)\\C=37.68\ in^$

4 0

2 years ago

In art class, Arthur has created a triangle painting 1/5 of his painting is purple. He decided he wants to Paint 4/8 of the purp

babymother [125]

$\frac{1}{10}$ part of the whole painting is gold colored.

<u>Solution:</u>

Given that , In art class, Arthur has created a triangle painting $\frac{1}{5}$ of his painting is purple.

He decided he wants to Paint $\frac{4}{8}$ of the purple area gold

We have to find what fraction of the whole painting will be painting?

Now, $\frac{1}{5}$ part of whole painting is purple

And, $\frac{4}{8}$ part of the purple area is gold ⇒ $\frac{4}{8}$ part of the $\frac{1}{5}$ part of whole painting is gold

$\text { Then, fraction of gold color }=\frac{4}{8} \times \frac{1}{5}=\frac{1}{2} \times \frac{1}{5}=\frac{1}{10}$

Hence, $\frac{1}{10}$ part of the whole painting is gold colored.

4 0

3 years ago