Solve by factoring. m^2+8m+7=0 A. 8,7 B. -7,1 C. -7,-1 D. 7,1

Mathematics

1 answer:

REY [17]3 years ago

5 0

The answer is c, -1 or -7

Hope this helped :)

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Write a fraction, a decimal, and a percent that sum to 1 or 100%.

NemiM [27]

Answer:

Fraction: 1/1, 2/2, 3/3, 4/4, 5/5, 6/6, 7/7, 8/8, 9/9, 10/10 etc.

Decimal: 1.00

Percent: 100%

3 0

3 years ago

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If p is a polynomial show that lim x→ap(x)=p(a

Lostsunrise [7]

Let p(x) be a polynomial, and suppose that a is any real number. Prove that

lim x→a p(x) = p(a) .

Solution. Notice that

2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .

So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x – 2.

Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| < 1, so −2 < x < 0. In particular |x| < 2. So

|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|

= 2|x|^3 + 5|x|^2 + |x| + 2

< 2(2)^3 + 5(2)^2 + (2) + 2

= 40

Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2 + x − 2| < ε/40 · 40 = ε.

3 0

3 years ago

Find the slope of the line through each pair of points (6, -10) , (-15 , 15)

dem82 [27]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\bf \leadsto The \ slope \ of \ the \ line \ is \ \dfrac{-25}{21}.}}}$

<h3>Step-by-step explanation:</h3>

Two points are given to us and we need to find the slope of the line . The slope of the line passing through points $\bf (x_1,y_1 ) \ \& \ (x_2,y_2)$ is given by ,

$\qquad\boxed{\red{\bf Slope = tan\theta=\dfrac{y_2-y_1}{x_2-x_1}}}$

Here , the points are ,

( 6 , -10 )
( -15 , 15 )

$\bf\implies Slope = \dfrac{y_2-y_1}{x_2-x_1} \\\\\bf\implies Slope =\dfrac{15-(-10)}{-15-6} \\\\\bf\implies Slope = \dfrac{15+10}{-21}\\\\\bf\implies Slope =\dfrac{-1(25)}{-1(-21)}\\\\ \bf\implies\boxed{\red{\bf Slope =\dfrac{-25}{21}}}$