Solve by factoring. m^2+8m+7=0 A. 8,7 B. -7,1 C. -7,-1 D. 7,1

A toll bridge charges $1.00 for passenger cars and $2.25 for other vehicles. Suppose that during daytime hours, 60% of all vehic

lora16 [44]

Answer:

Total revenue = 13.5 + 9 = $22.5

Step-by-step explanation:

The toll charges $1.00 for passenger cars and $2.25 for other vehicles. During daytime hours 60% of all the vehicles are passenger vehicles.

A particular daytime period 15 vehicle crossed the bridge. Recall that during daytime period, 60% of all the vehicles are passenger vehicles . Therefore,

Passenger vehicles = 60% of 15

Passenger vehicles = 60/100 × 15

Passenger vehicles = 900/100

Passenger vehicles = 9

9 of the vehicles are passenger vehicle and the charges for passenger cars is $1.00. other vehicle is $2.25.

revenue for passenger cars = 1 × 9 = $9

revenue for other vehicles = 2.25 × 6 = $13.5

Total revenue = 13.5 + 9 = $22.5

8 0

3 years ago

Nola hiked down a trail at a steady rate for 10 minutes. Her change in elevation was -200 ft. Then she continued to hike down fo

umka21 [38]

Her first rate was faster. The 10 minutes with a change in elevation of -200ft.
In order to solve this you need to have the same minutes. In this problem, I just simply took the 10 minutes and the -200ft and doubled it. Now both rates have 20 minutes. The first rate would have gone -400ft in 20 minutes while the second rate was only -300ft in 20 minutes. I hope this wasn't confusing, and I'm willing to explain more.

7 0

3 years ago

Mike wants to fence in part of his backyard. He wants the length of the fenced-in area to be at least 20 feet long, l ≥ 20. He h

zhuklara [117]

I added a screenshot of the complete question along with the given choices.

Answers:

w = 10 ft and l = 50 ft ................> second option

w = 20 ft and l = 60 ft ...............> third option

w = 50 ft and l = 40 ft ...............> fifth option

Explanation:

We are given that:

length should be at least 20 ...........> length ≥ 20

equation for perimeter is : 2l + 2w ≤ 200

We will check each option as follows:

Option 1:

w = 50 ft and l = 10 ft

This option is incorrect as the proposed length is less than 20.

Option 2:

w = 10 ft and l = 50 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(50) + 2(10) = 100 + 20 = 120 ≤ 200

The second condition is also satisfied.

This option is correct

Option 3:

w = 20 ft and l = 60 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(60) + 2(20) = 120 + 40 = 160 ≤ 200

The second condition is also satisfied.

This option is correct

Option 4:

w = 90 ft and l = 30 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(30) + 2(90) = 60 + 180 = 240 > 200

The second condition is not satisfied.

This option is incorrect

Option 5:

w = 50 ft and l = 40 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(50) + 2(40) = 100 + 80 = 180 ≤ 200

The second condition is also satisfied.

This option is correct

Hope this helps :)

8 0

3 years ago

Read 2 more answers

A standard deck of playing cards contains 52 cards, equally divided among four suits (hearts, diamonds, clubs, and spades). Each

Svetradugi [14.3K]

The order does not matter, so we will be using combinations here. 52C1 is the first one since there is only one possibility. 16C1 is the second. You have to multiply these two, so 52 X 16 = 832.

3 0

3 years ago

If g(X) = 2x-1 , then what is g(3)?

Tanzania [10]

2(3)-1
6-1
5
Good luck :)

7 0

3 years ago