You have the right idea that things need to get multiplied.
What should be done is that the entire fraction needs to get multipled by the lowest common denominator of both denominators.
Let's look at the complex numerator. Its denominators are 5 and x + 6. Nothing is common with these, so both pieces are needed.
The complex denominator has x - 3 as its denominator. With nothing in common between it and the complex numerator, that piece is needed.
So we multiply the entire complex fraction by (5)(x + 6)(x -3).
Numerator: 
= (x+6)(x-3) - (5)(5)(x-3)
= (x+6)(x-3) - 25(x-3)
= (x-3)(x + 6 - 25) <--- by group factoring the common x - 3
= (x -3)(x - 19)
Denominator:
Now we put the pieces together.
Our fraction simplies to (x - 3) (x - 19) / 125 (x + 6)
Answer:
The polynomial 3x² + x - 6x + 3 is a prime polynomial
How to determine the prime polynomial?
For a polynomial to be prime, it means that the polynomial cannot be divided into factors
From the list of options, the polynomial (D) is prime, and the proof is as follows:
We have:
3x² + x - 6x + 3
From the graph of the polynomial (see attachment), we can see that the function does not cross the x-axis.
Hence, the polynomial 3x² + x - 6x + 3 is a prime polynomial
Read more about prime polynomial at:
brainly.com/question/2944912
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I believe they are: (2,8), (4,6), (1,7), and (3,5) I could be wrong, but I'm almost certain that's it. Hope that helps.
Answer:
Step-by-step explanation:
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined. y=6 is a straight line perpendicular to the y-axis at point (0,6) , which means that the range is a set of one value {6} .
For the largest area, half the fence is used parallel to the river, and the other half is used for the two ends of the rectangular space.
The dimensions are 475 m by 237.5 m.
_____
Let x represent the length along the river. Then the area (A) is found as
.. A = x*(950 -x)/2
This equation describes a parabola with its vertex (maximum) halfway between the zeros of x=0 and x=950. That is, the maximum area is achieved when half the fence is used parallel to the river.
