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1 answer:

iren [92.7K]2 years ago

7 0

I believe to know that the answer is Dcm

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Find the constant $a$ such that\[(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28.\]

Colt1911 [192]

The value of constant a is -5

Further explanation:

We will use the comparison of co-efficient method for finding the value of a

So,

Given

$(x^2 - 3x + 4)(2x^2 +ax + 7)\\= x^2((2x^2 +ax + 7)-3x((2x^2 +ax + 7)+4(2x^2 +ax + 7)\\= 2x^4+ax^3+7x^2-6x^3-3ax^2-21x+8x^2+4ax+28\\Combining\ alike\ terms\\=2x^4+ax^3-6x^3+7x^2-3ax^2+8x^2-21x+4ax+28\\= 2x^4 +(a-6)x^3+(15-3a)x^2-(21-4a)x+28\\$

As it is given that

(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28

In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x

Comparing coefficient of x^3

$a-6 = -11\\a = -11+6\\a = -5$

So the value of constant a is -5

Keywords: Polynomials, factorization

Learn more about factorization at:

#LearnwithBrainly

4 0

3 years ago

Solve 8(x+2)=36.......

brilliants [131]

We have to use the Distributive Property in this equation.
By the Distributive Property,
$8(x+2)=36
$
becomes
$8x+16=36.$
Now we need to isolate x. Remember PEMDAS?
$8x=20$
$x=20/8$
Simplify the right side.
$x=10/4$
$x=5/2$

3 0

2 years ago

Read 2 more answers

What is the solution of this question.<br> 9988 ÷ 23 =

gizmo_the_mogwai [7]

Answer:

$434\frac{6}{23}$