Answer:
1.x = pi/3 or 4pi/3
2. x = -pi/6 +2pi*n or 5pi/6 + 2pi *n where n is an integer
Step-by-step explanation:
1. sqrt(3) tan x = 3
Divide each side by sqrt(3)
sqrt(3)/sqrt(3) tan x = 3/sqrt(3)
tan x = sqrt(3) * sqrt(3)/sqrt(3)
tan x = sqrt(3)
Take the inverse of each side
arctan (tanx) = arctan (sqrt(3))
x = arctan (sqrt(3))
x =pi/3 or - 2pi/3
Since the domain is between 0 and 2pi, add 2pi to - 2pi/3 since the trig functions are circular
x = pi/3 or -2pi/3 + 6pi/3
x = pi/3 or 4pi/3
2. 3 tan x = -sqrt(3)
Divide each side by 3
3/3 tan x = -sqrt(3)/3
tan x = -sqrt(3)/3
Take the arctan of each side
arctan (tan x) = arctan ( -sqrt(3)/3)
x = arctan ( -sqrt(3)/3)
x =-pi/6 or 5pi/6
We want all values for x so add 2pi*n to each value where n is an integer
x = -pi/6 +2pi*n or 5pi/6 + 2pi *n where n is an integer
You basically plug in numbers..I will use positive integers.
You basically plug in numbers for x to find the y .
0,1
1,-2
2,-5
3,-8 and so on
Answer:
A
Step-by-step explanation:
i hope this is right
Answer:
Step-by-step explanation:
bottom left is 13a + 2b
bottom right is 15y - 6
The solution to system is x = 0 and y = -1
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-8x + 2y = -2 ----------- eqn 1
4x + 4y = -4 ---------- eqn 2
We have to solve the system of equations
We can solve the equations by elimination method
<em><u>Multiply eqn 2 by 2</u></em>
8x + 8y = -8 ------ eqn 3
<em><u>Add eqn 1 and eqn 3</u></em>
-8x + 2y = -2
8x + 8y = -8
( + ) ---------------
0x + 2y + 8y = -2 - 8
10y = -10
Divide both sides by 10
y = -1
<em><u>Substitute y = -1 in eqn 1</u></em>
-8x + 2(-1) = -2
-8x - 2 = -2
-8x = -2 + 2
x = 0
Thus the solution to system is x = 0 and y = -1
