suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Answer is x² + 2x + 5
<u>Step-by-step explanation:</u>
Step 1:
Add the two polynomials
⇒ (2x + 7) + (x² - 2) = 2x + 7 + x² - 2 = x² + 2x + 5
The answer is going to be
Paris paid 180$ more than Chandler in taxes
Answer:
c
Step-by-step explanation: