Simplify the <u>expression</u>.
2m
Option D, 63 cm
Explanation:
The scale of model is of local park is
This means that each dimension of the model is 21 times smaller than the actual park (to be developed in future)
Given -
Depth of the pond centi meter
Depth of the real pond will be 21 times of the depth of the model.
Thus , real pond's depth is equal to
cm
Hence, option D is correct
9514 1404 393
Answer:
no solution
Step-by-step explanation:
The discriminant is ...
b^2 -4ac = (-4)^2 -4(2)(16) = 16 -128 = -112
A negative discriminant means there are no real solutions to the equation.
_____
The complex solutions are 1±i√7.
If we assume the equation has a typographical error and is intended to be ...
2x^2 -4x -16 = 0
The solutions are x = -2 and x = 4.
Answer:
the slope is flatter
the line is shifted 7 down
Step-by-step explanation:
Answer:
55 degrees is more unusual in July as it is away from mean temperature as compared to January.
Step-by-step explanation:
We are given the following information in the question:
January:
Mean, μ = 36 degrees
Standard Deviation, σ = 10 degrees
July:
Mean, μ = 74 degrees
Standard Deviation, σ = 8 degrees
We calculate z scores corresponding to x = 55.
Formula:

January:

July:

Thus, 55 degrees is more unusual in July as it is away from mean temperature as compared to January.