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3 years ago

An education budget went from $800,000 to $900,000. what is the approximate percent increase?

2 answers:

6 0

First, calculate the difference between the two given budgets. $900,000 - $800,000 = $100,000. Divide the difference obtained by the original budget and then multiply by 100%
($100,000 / $800,000) x 100% = 12.5%

Thus, the answer to the question above is that the percent increase is 12.5%.

sergiy2304 [10]3 years ago

5 0

Answer: 12.5 %

Step-by-step explanation:

Previous education budget=$800,000

Next education budget= $900,000

Increase in education budget= Next education budget-Previous education budget

$=\$900,000-\$800,000\\=\$100,000$

Percent increase $=\frac{\text{Increase in education budget}}{\text{Previous education budget}}\times100$

$=\frac{\$100,000}{\$800,000}\times100$

$=\frac{1}{8}\times100\\\\=12.5\%$

The approximate percent increase is 12.5%.

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DanielleElmas [232]

Answer:

C) 100 m^2

Step-by-step explanation:

Area of a trapezoid= h*[(b1+b2)/2]

h=10

b1=8

b2=12

Therefore:

A=10*[(8+12)/2]

A=10*(20/2)

A=10*10

A=100

So the area of the trapezoid is 100 m^2

7 0

3 years ago

Please show full solutions! WIll Mark Brainliest for the best answer. SERIOUS ANSWERS ONLY

Ierofanga [76]

Answer:

vertical scaling by a factor of 1/3 (compression)
reflection over the y-axis
horizontal scaling by a factor of 3 (expansion)
translation left 1 unit
translation up 3 units

Step-by-step explanation:

These are the transformations of interest:

g(x) = k·f(x) . . . . . vertical scaling (expansion) by a factor of k

g(x) = f(x) +k . . . . vertical translation by k units (upward)

g(x) = f(x/k) . . . . . horizontal expansion by a factor of k. When k < 0, the function is also reflected over the y-axis

g(x) = f(x-k) . . . . . horizontal translation to the right by k units

Here, we have ...

g(x) = 1/3f(-1/3(x+1)) +3

The vertical and horizontal transformations can be applied in either order, since neither affects the other. If we work left-to-right through the expression for g(x), we can see these transformations have been applied:

vertical scaling by a factor of 1/3 (compression) . . . 1/3f(x)
reflection over the y-axis . . . 1/3f(-x)
horizontal scaling by a factor of 3 (expansion) . . . 1/3f(-1/3x)
translation left 1 unit . . . 1/3f(-1/3(x+1))
translation up 3 units . . . 1/3f(-1/3(x+1)) +3

_____

Additional comment

The "working" is a matter of matching the form of g(x) to the forms of the different transformations. It is a pattern-matching problem.

The horizontal transformations could also be described as ...

translation right 1/3 unit . . . f(x -1/3)
reflection over y and expansion by a factor of 3 . . . f(-1/3x -1/3)

The initial translation in this scenario would be reflected to a translation left 1/3 unit, then the horizontal expansion would turn that into a translation left 1 unit, as described above. Order matters.