Answer:
5. LCM of 7 and 14: <u> </u><u> </u><em><u>1</u></em><em><u>4</u></em><em><u>. </u></em>
multiples of 7: <u> </u><u> </u><u>7</u><u>,</u><u> </u><u>1</u><u>4</u><u> </u>
multiples of 14: <u> </u><u>1</u><u>4</u><u> </u>
LCM of 8 and 12: <u> </u><u> </u><em><u>2</u></em><em><u>4</u></em><em><u>. </u></em>
multiples of 8: <u> </u><u> </u><u>8</u><u>,</u><u> </u><u>1</u><u>6</u><u>,</u><u> </u><u>2</u><u>4</u><u> </u>
multiples of 12: <u> </u><u> </u><u>1</u><u>2</u><u>,</u><u> </u><u>2</u><u>4</u><u> </u>
Step-by-step explanation:
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Arrange them first
4,5,5,6,10,11,12,13
These are 8 numbers.we will divide the sum of middle 2 numbees on 2.
6+10=16÷2
8..median
Answer:
1, 2, 4, 7, 14, 28, 49, 98, and 196.
Step-by-step explanation:
Answer:
0.9056
Step-by-step explanation:
We are given;
Number of students enrolled in both General Chemistry and Calculus I = 540 students
Number of students who received an A in general chemistry = 51 students
Number of students who received an A in calculus = 59 students
Number of students who received an A in both general chemistry and calculus = 30 students
Now, we want to find the probability that a randomly chosen student did not receive an A in general chemistry.
So, first of all let's calculate number of students who didn't receive an A in chemistry.
So,
No without A in chemistry = 540 - 51 = 489 students
So, probability that a randomly chosen student did not receive an A in general chemistry = 489/540 = 0.9056