In the right triangle shown,

Help me please

Goshia [24]

Midpoint is (-2 , -0.5)

6 0

2 years ago

Does the order pair, (2,3) satisfy the following function y=-3x-2 Yes,No

grin007 [14]

Answer:

No

Step-by-step explanation:

The function y=-3x-2 does not go through the ordered pair (2,3).

3 0

2 years ago

Raymond is building a fence for a dog run. the dog run will be a rectangle with a length of 24 feet and a width that is 2/5 the

Cerrena [4.2K]

Answer:

The perimeter of the dog run will use 67.2 feet of fencing.

Step-by-step explanation:

First find how long the width is.

24 * 2/5 = 9.6

The width of the fence is 9.6 feet.

To find the total perimeter, add double the length and width.

24 * 2 = 48

9.6 * 2 = 19.2

48 + 19.2 = 67.2

3 0

2 years ago

Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation
Coordinates (x, y)

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

Step 2: Find General Solution

Use integration

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$