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Illusion [34]
3 years ago
5

HELP ASAP "Steve's mom gives him 50$ to spend at the mall. He must but two new pairs of pants which each cost 19$ each. He can s

pend the rest at an arcade where each game cost 0.75
Which inequality can be used to determine the number (n) of arcade games Steve can play?


19 + 0.75n <50

19 + 0.75, n , <50

38 + 0.75n <50

38 + 0.75, n , <50

19 + 0.75n ≤50

19 + 0.75, n is less than or equal to, 50

38 + 0.75n ≤50
Mathematics
2 answers:
monitta3 years ago
4 0
I really don’t know I’m sorry:(
Mademuasel [1]3 years ago
3 0

Answer:

bro i'm literally doing math homework right now and i don't know ANYTHING about it. so dude i def cant help u i'm sorry :')

Step-by-step explanation:

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Please help. All you have to do is write a simple expression but I don't fully under stand it so please help me. This is due tod
Semenov [28]

Answer:

1497 - 202

Step-by-step explanation:

The question is saying that the Las Vegas trip was longer so we know to put that first in the expression

we can also tell that the question is asking us for the difference (aka subtraction)  between the two trip by the key words <em>how much longer</em>

and then it tells us that we are finding the difference between Las Vegas and Cheyenne so we know to use those two numbers

that is how we come up with the expression 1497 - 202

7 0
3 years ago
Twenty-four students tried out for the cheerleading squad. Only 5/6 of the
IceJOKER [234]

Step-by-step explanation:

Total no. of students tried out for the cheerleading squad = 24

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\frac{5}{6}  \times 24

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6 0
3 years ago
I will mark you brainliest if you answer this
zhenek [66]

\huge\color{purple}\boxed{\colorbox{black}{♡Solution}}

8.

7 {x}^{3}  + 3 {x}^{2}  + 4x + 10 - 10 - 8x - 3 {x}^{3}  \\  = 7 {x}^{3}  - 3 {x}^{3}  + 3 {x}^{2}  + 4x - 8x + 10 - 10 \\  = 4 {x}^{3}  + 3 {x}^{2}- 4x

9.

5 {x}^{4}  - 4 {x}^{3}  - 3x - 4 - 2x + 6 {x}^{3}  + 2 {x}^{4}  \\  = 5 {x}^{4}  + 2 {x}^{4}  - 4 {x}^{3}  + 6 {x}^{3}  - 3x - 2x - 4 \\  = 7 {x}^{4}  + 2 {x}^{3}  - 5x - 4

10.

7 {x}^{3}  - 9 {x}^{2}  - 7x - 8 - 8 + 4 {x}^{2}  + 6 {x}^{3}  \\  = 7 {x}^{3} + 6 {x}^{3}   - 9 {x}^{2}  + 4 {x}^{2}  - 7x - 8 - 8 \\  = 13 {x}^{3}  - 5 {x}^{2}  - 7x - 16

11.

4a + 20 - 5 {a}^{2}  + 20a - 35 \\  =  - 5 {a}^{2} +  24a - 15

12.

8y + 48 - 6 {y}^{2}  + 36y - 24 \\  =  - 6 {y}^{2}  + 44y + 24 \\  = 2( - 3 {y}^{2}  + 22y + 12)

13.

3c - 12 - 5 {c}^{2}  - 20c + 40 \\  =  - 5 {c}^{2}  - 17c + 28

\large\mathfrak{{\pmb{\underline{\orange{Mystique }}{\orange{♡}}}}}

7 0
3 years ago
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