Step-by-step explanation:
here,
x°+15°=5x°-41°[being vertically opposite angle]
15°+41°=5x°-x°
56°=4x°
thus,x=14°
<h3>hence,the value of x is 14°.</h3><h2>I hope this will help you.</h2><h2>please mark my answer as BRAINLIEST if you liked it....</h2>
Oooooffffffff im pretty positive that this is true
First, the formula of the circumference.
There are two formulas:
1. C = π*d
[Note: d = diameter]
2. C = 2*π*r
[Note: r = radius]
[Note: This symbol * means to multiply.]
Since we are given the diameter, it’s easier to use the first formula, π*d. Let’s not be too hard on ourselves.
Okay, so let’s state our decided formula:
C = π*d
Then replace d with the car tire’s diameter:
C = π*(32)
Afterwards, find a calculator and multiply π with 32. You will get 100.5309649 as result.
If where to round is stated in your question, round to that. If not, it’s best to round by two decimal places. In this case, we’ll round 100.5309649 to 100.53.
Please add your units as well. In this case, the final answer will be: 100.53 inches.
Since this is a word problem, don’t forget your final statement!
“The approximate circumference of the tire is 100.53 inches.”
Answer:
-3 ≥ x ≥ 9
Step-by-step explanation:
The domain are the x-values of every point in your graph. Since it a continuous domain, it'll be represented with ≥. Your two extremities are -3 and 9. Therefore, your domain is -3 ≥ x ≥ 9.
There are 2 variables in this problem. One variable is the class number and other variable is the participation in extracurricular activities. Each variable has further two categories. There are two classes: Class 10 and 11. And students either participate or do not participate in extracurricular activities, which makes 2 categories.
The best approach to solve this question is to build a table and start entering the given information in it. When the given data has been entered fill the rest on basis of the data you have.
18 students from grade 11 participate in at least one Extracurricular activities. This means the rest students i.e. 22 students from grade 11 do not participate in Extracurricular activities.
32 students from grade 10 participate in at least one Extracurricular activities. This means total students who participate in at least one Extracurricular activities are 18 + 32 = 50 students.
The rest 50 students do not participate in at least one Extracurricular activities. From these 22 are from class 11. So the rest i.e. 28 are from class 10.
