It typically just needs two parts
1) all parties must be in agreement
2) something of value needs to be exchanged. ie. money, a service
Answer:
a)120
b)6.67%
Step-by-step explanation:
Given:
No. of digits given= 6
Digits given= 1,2,3,5,8,9
Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be
6P3= 6!/3!
= 6*5*4*3*2*1/3*2*1
=6*5*4
=120
Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:
As the first and last digits can only be even
then the form of number can be
a)2n8 or
b)8n2
where n can be 1,3,5 or 9
4*2=8
so there can be 8 three-digit numbers with both the first digit and the last digit even numbers
And probability = 8/120
= 0.0667
=6.67%
The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !
See, please, the suggested option.
If it possible, check it in other sources.
Answer:10000
Step-by-step explanation:
Remember that log x and 10^x are inverse functions.
If you have log x = 4 and want the value of x, write this out:
log x 4
10 = 10
This simplifies to:
x = 10^4, and so the fourth answer choice is the correct one.
Answer:
The input in this equation is c(v), and the output is 125v. For example, if you input 2 into c(v) and get c(2), you will get 125(2) = 250 for two visits.
