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photoshop1234 [79]
3 years ago
12

Please help with this question

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

for x=i

Step-by-step explanation:

For

1+x²=0 => x²= -1 => x=√-1 => x= i

the given equation is not true

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7. If the volume of a cylinder, where the height is 3 times the radius, is 247, find the surface area of the cylinder.
lakkis [162]

Answer:

3.87987×10^5

Step-by-step explanation:

surface area of the cylinder =2πrh+2πr²

=2*π*247*3+2*π*(247)²

=3.87987×10^5

7 0
3 years ago
What are the next two numbers in the pattern 3,6,5,10,9,18,17.
LenKa [72]
This pattern appears to alternate between doubling and subtracting by 1. 

To get from 3 to 6, we multiply by two.
To get from 6 to 5, we subtract one.
To get from 5 to 10, we multiply by two.
To get from 10 to 9, we subtract one.
To get from 9 to 18, we multiply by two.
To get from 18 to 17, we subtract one.

Therefore, next we need to multiply by two.
17 x 2 = 34
So, the next number is 34.

To find the number after, we subtract one.
34 - 1 = 33
Thus, the number after is 33.

In conclusion, the next two numbers are 34 and 33.
6 0
3 years ago
Read 2 more answers
Can you graph X-intercept -3,-2,-1,1 and Y-intercept 5,2,-1,-3
arlik [135]

--Answer--

It's in the picture, desmos will help for graphing.

7 0
3 years ago
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Solve the problem. The half-life of plutonium-234 is 9 hours. If 50 milligrams is present now, how much will be present in 6 day
MaRussiya [10]

Answer:

  4)  0.001

Step-by-step explanation:

The amount (a) present in h hours is ...

  a(h) = (initial value)×(1/2)^(h/(half-life))

6 days is 6×24 hours, so the amount remaining is ...

  a(6×24) = 50×(1/2)^(6×24/9) = 50/2^16 ≈ 0.001 . . . . milligrams

3 0
3 years ago
Use the quadratic formula to find the solutions for..<br> y = 2x^2 - 9x + 5.
Yakvenalex [24]

Answer: x=\frac{9}{4}-\frac{\sqrt{41} }{4}  \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}

Step-by-step explanation:

2x^2-9x+5

a=2

b=-9

c=5

x=\frac{-b\frac{+}{}\sqrt{b^2-4ac}  }{2a}

x=\frac{-(-9)\frac{+}{}\sqrt{(-9)^2-4(2)(5)}  }{2(2)}

x=\frac{9\frac{+}{}\sqrt{81-40}  }{4}

x=\frac{9\frac{+}{}\sqrt{41}  }{4}

x=\frac{9}{4}-\frac{\sqrt{41} }{4}  \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}

4 0
3 years ago
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