I would say to do 637000-437000, which is 200000, and then do 200000/637000. You get 0.314, and the percentage of that in hundreds is 31%.
<em>The result can be shown in both exact and decimal forms.
</em>
<em>Exact Form:
</em>
<em>4
e
+
21
</em>
<em>Decimal Form:
</em>
<em>31.87312731
…</em>
Thanks,
<em>Deku ❤</em>
Hello There!
To find the mean, add up all the numbers and divide according to how many numbers there are. The mean for this set would be <em>"9"</em>
<em></em>
To find the median, place the numbers in value order and find the middle. if there is no middle, add up the two numbers in middle and divide by 2. In this set, the median would be <em>"8.5"</em>
<em></em>
To find the mode or modal value, it is best to put the numbers in order. Then count how many of each number. A number that appears most often is the mode. In this set, there would be no mode.
The range of a set of data is the difference between the highest and lowest values in the set. In this set, the range would be <em>"12"</em>
Step-by-step explanation:
Claim: There's 14 Goats and 9 Chickens!!
Data:
Working with the Provided Information.
Let the Number of goats be x
let the Number of Chickens be y
x + y = 23..... (i)
Since the goat Possesses Two Pair of Legs... Which is a Total of 4 Legs... We say Let its Contribution be 4x.
The Chicken has Only a Pair Of Legs...Which is a total of 2 legs.... We say let its contribution be 2y
4x + 2y = 74 .....(ii)
BRINGING BOTH EQUATIONS TOGETHER.
x + y = 23
4x + 2y = 74
From Eqn i
x= 23 - y
Substitute into eqn ii
4(23 - y ) + 2y = 74
92 - 4y + 2y = 74
92 - 2y = 74
2y = 92 - 74
2y = 18
y= 9.
Substitute y into any of the eqns to get x
x + y = 23
x + 9=23
x = 23 - 9
x = 14
This simply proves that there are 14 Goats and 9 Chickens!!!.
HAVE A GREAT DAY!
Answer:
width = x+2
Step-by-step explanation:
area/length = width
(x^2+9x+14) / (x+7) =?
(x+7)(x+2) / (x+7) = x+2
