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notsponge [240]
3 years ago
8

To bisect an angle using paper folding, fold the paper through the angle so that the line segments determining the angle lie:

Mathematics
2 answers:
algol [13]3 years ago
6 0
To bisect an angle using paper folding, fold the paper through the angle so that the line segments determining the angle lie ON EACH OTHER. 

To bisect means to divide into two equal parts and to find the middle line of the shape or angle. Simply fold the paper using the written lines of an angle. Each line must lie on each other, flatten the paper and the crease formed will be the bisecting line. 

Svetlanka [38]3 years ago
3 0

Answer:

On each other

Step-by-step explanation:

APEX

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To make 6 apples pie, you need 2 pounds of apples. How many pounds of apples do you need to make 10 apple pies?
Bezzdna [24]
For every 6 apple pie, you need 2 pounds of apples.
So, how many pounds of apples do you need for 10 apple pies?
Well, first to figure out this question we first need to make a conversion factor.
I see in the fraction 6/3 we can simplify that to 2/1. Now we got our conversion factor.
We need to invert the fraction in order for the pie unit to cancel out.
1/2 * 10 = 5

You will need 5 pounds of apples to make 10 apple pies.

4 0
3 years ago
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The following set of coordinates represents which figure? (1,1), (5,3), (7,7), (3,5)
marishachu [46]

Answer:

1×1÷11. 5×3=15. 7×7=49 3×5=15 I'm not really sure but is there's anything else

3 0
3 years ago
Write 900,000+80,000+500+7 in standard form
Gnoma [55]
900,000+80,000+500+7 is 980,507
4 0
4 years ago
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Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
Please help due soon!
soldi70 [24.7K]
H = 2sqrt2
D = 6sqrt3

In a 45,45,90 triangle the hypotenuse is (x)sqrt2 while the side lengths are equivalent being a single value x. Therefore, when given the hypotenuse and solving for the leg, divide 4 by sqrt2 to get 4sqrt2/2 which simplifies to 2sqrt2 when the denominator and numerator cancel.

In a 30,60,90 triangle the short leg x is across from the 30 degree angle meaning the angle across from the 60 degree angle is x times the sqrt of 3. Therefore the long leg is 6sqrt3
5 0
3 years ago
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