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lana66690 [7]
2 years ago
7

What is the area of the figure?

Mathematics
1 answer:
Finger [1]2 years ago
7 0

Answer:

Given a figure that is broken into a rectangle and triangle.

The dimensions of the rectangle are:

Base : 5 ft

Height : 1/3 ft

The dimensions of the triangle are :

Base : 3 upon 2/3 ft

Height : 2 ft

The area of the figure calculated below :-

Area of rectangle + Area of triangle

Area of rectangle + Area of triangleLB + 1/2BH

(5×1/3) + (1/3+3upon2/3×2)

The result is simplified below :-

5/3+11/3

5+11/3

16/3 ft

51/3 ft square.

The area of the figure is 5 and one third square feet.

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What is the area of this figure?
nalin [4]

Answer:

<em>290.5 square miles</em>

Step-by-step explanation:

Consider splitting this figure into two mini rectangles and a triangle, each of given lengths;

Dimensions of Rectangle 1 - Height ; 5 mi, Length ; 7 mi,\\Area of Rectangle 1 - Height * Length = 5 mi * 7 mi = 35 mi^2\\\\Dimensions of Rectangle 2 - Height ; 18 mi, Length ; 8 mi,\\Area of Rectangle 2 - Height * Length = 23 mi * 8 mi = 184 mi^2\\\\Dimensions of Mini Right Triangle - Height ; 11 mi, Base ; 8 + 5 = 13 mi,\\Area of Mini Right Triangle - 1 / 2 * Base * Height = 1 / 2 * 13 mi * 11 mi = 71.5 mi^2,\\\\Area of Figure = 35 mi^2 + 184 mi^2 + 71.5 mi^2 = 290.5 square miles

<em>Solution; 290.5 square miles</em>

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3 years ago
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What is the correct answer?
Tasya [4]

Given:

The function is

f(x)=(x+3)^2(x-5)^6

To find:

The zeros of the given function.

Solution:

The general form of polynomial is

P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}       ...(i)

where, a is a constant, c_1,c_2,...,c_n are zeros of respective multiplicities m_1,m_2,...,m_n.

We have,

f(x)=(x+3)^2(x-5)^6

On comparing this with (i), we get

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It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.

Therefore, the correct option is B.

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3 years ago
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