Answer:
Given a figure that is broken into a rectangle and triangle.
The dimensions of the rectangle are:
Base : 5 ft
Height : 1/3 ft
The dimensions of the triangle are :
Base : 3 upon 2/3 ft
Height : 2 ft
The area of the figure calculated below :-
Area of rectangle + Area of triangle
Area of rectangle + Area of triangleLB + 1/2BH
(5×1/3) + (1/3+3upon2/3×2)
The result is simplified below :-
5/3+11/3
5+11/3
16/3 ft
51/3 ft square.
The area of the figure is 5 and one third square feet.
