The inclination to the nearest tenth of a degree exists 0.24146
<h3>What is the inclination to the nearest tenth of a degree?</h3>
The given scenario includes a right-angled triangle where the length of the ramp exists hypotenuse and the rise of ramp exists the perpendicular.
Given: H = 4.6 m and P = 1.1 m
We have to use the trigonometric ratios to find the angle. The ratio that has to be used should involve both perpendicular and hypotenuse
Let x be the angle then
sin x = P/H
sin x = 1.1/4.6
sin x = 0.23913
= 0.24146
The inclination to the nearest tenth of a degree exists 0.24146
To learn more about trigonometric ratios refer to:
brainly.com/question/14033725
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<h3>
Answer: y^4 - 2y^3 + 7y^2 + y - 5</h3>
Work Shown:
h(y) = f(y) + g(y)
h(y) = (y^4 - 3y^3 + y - 3) + (y^3 + 7y^2 - 2)
h(y) = y^4 - 3y^3 + y - 3 + y^3 + 7y^2 - 2
h(y) = y^4 + (-3y^3+y^3) + 7y^2 + y + (-3 - 2)
h(y) = y^4 - 2y^3 + 7y^2 + y - 5
This is a fourth degree polynomial (aka quartic).
Answer: its 18.27
Step-by-step explanation:
Answer:
13
Step-by-step explanation:
If he reads 119 pgs in 7 days that mean 119/7 = 17 he reads 17 pgs per day
next 340-119 = 221 then 221/17= 13
An equvilent equation
remember you can do anything to an equation as long asyou do it to both sides
assuming yo have
x+y=1 and
x-3y=9
mulitply both by 2
2x+2y=2
2x-6y=18
those are equvilent
ok, solve initial
x+y=1
x-3y=9
multiply first equation by -1 and add to 2nd equation
-x-y=-1
<u>x-3y=9 +</u>
0x-4y=8
-4y=8
divide both sides by -4
y=-2
sub back
x+y=1
x-2=1
add 2
x=3
x=3
y=-2
(3,-2)
if we test it in other one
2x+2y=2
2(3)+2(-2)=2
6-4=2
2=2
yep
2x-6y=18
2(3)-6(-2)=18
6+12=18
18=18
yep
solution is (3,-2)
