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sveta [45]
1 year ago
12

1. There are red and blue marbles in a bowl.

Mathematics
1 answer:
kkurt [141]1 year ago
4 0

Answer:

2r, where r is the number of red marbles

Step-by-step explanation:

Since there is twice as many blue marbles as red marbles, it infers blue marbles = 2 × red marbles.

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What is the value of 3 in 6300 and 530
mojhsa [17]
The value of three in 6,300 is 3,000 because it is in the thousands place. The three in 530 is in the hundreds place making the value of three 300.  Hope that this helps you :D
5 0
3 years ago
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A company that makes hair-care products had 3,000 people try a new shampoo of the 3,000 21 had a mild allergic reaction. What pe
Ksenya-84 [330]

Answer:

.007

Step-step explanation:

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5 0
3 years ago
9 to the power 3 + 3 to the power 2 + 6 to the power 3 + 15 power 2 equals to how much
Llana [10]
Hey! So, here's a tip. When writing exponents, an easier way is to write a^b, rather than a to the b power. Besides that, here is your answer!


So-------

9^3=729

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6^3=216

15^2=225



Now that we have that figured out, we can add them together, wish is simple. 729 + 9 + 216 + 225= 1,179.



Therefore, your final answer will be 1,174.




If you have any questions on this, I'm happy to help you. :)




3 0
3 years ago
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A diver descended at a constant rate of 16.05 feet every 3 minutes. Which of the following is true?
bekas [8.4K]
<span>Determine the lower limit of the 95% interval for the true mean weight. ... A diver descended at a constant rate of 12.24 feet every 3 minutes. .... weight of 16.05 ounces. at the 5% level of significance can we conclude that ...</span><span>

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5 0
3 years ago
Pls help me solve this question, also include step by step calculation ya. Thks
sp2606 [1]

\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}

Step-by-step explanation:

5x^2-x^2e^{2x}+2e^{2x}=10

Let:\ x^2=t  \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}

<em>Prologarithmize both parts of the equation:</em>

ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\

<u><em> Divide both parts of the equation by 2:</em></u>

\displaystyle\\x=\frac{ln5}{2}

t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}

6 0
1 year ago
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