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elixir [45]
3 years ago
6

(ii) 4xz? [- xyz + 3yz?]​

Mathematics
1 answer:
Goshia [24]3 years ago
3 0

Answer: -4x²z²y + 12xz²y

Step-by-step explanation:-------------

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QF Q6.) Find the function for a.
irakobra [83]
The function for a is (f o g) (x) = 8x^2-10.



Explanation

=========================
f(x)=2x-4, g(x)=4x^2-3, (f o g)=f(g(x))  

I already knew that the g of x is equal to 4x^2-3 so I substitute inside of the g of x

g(x)=4x^2-3 =======> f(x)=4x^2-3 =============> 2(4x^2-3)-4 

simplify it 
 
2(4x^2-3)-4  =======> 8x^2-6-4 =========> 8x^2-10

(f o g) = 8x^2-10


5 0
3 years ago
Read 2 more answers
HELP ! How do I graph y ≤1−3x
Zanzabum

Answer:

Step-by-step explanation:

\Select two x x values, and plug them into the equation to find the corresponding y y values.

8 0
2 years ago
Bevil and sona each got a big cookie.Sona gave Alfredo half her cookie,Bevil gave Alfredo one-third of his cookie. What fraction
Nikolay [14]
Alfredo got 1/6th of the Cookie
6 0
4 years ago
Solve for C:<br><br> C + 8 = -11<br><br> C = _____
stiv31 [10]
Well what +8 will be -11.
Let’s take this as positives.
8+11=19
Sooo
-19+8=-11
C=-19
7 0
3 years ago
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If a = {6 6 4 7 -4 4 -6 9 -3} and B= {1 5 -8 9 -5 -8 9 -5 2}, find 3a +9B Matrix operations
V125BC [204]

Answer:

3A+9B=\begin{bmatrix} 27 & 63 & -60 \\\\ 102 & -57 & -60\\\\ 63 & -18 & 9 \end{bmatrix}

Step-by-step explanation

  • A=\begin{bmatrix} 6 & 6 & 4\\\\7 & -4 & 4\\\\ -6 & 9 & -3\end{bmatrix}\: and \: B=\begin{bmatrix}1 & 5 & -8\\\\ 9 & -5 & -8\\\\ 9 & -5 & 2\end{bmatrix}

  • \rightarrow 3A=3\begin{bmatrix} 6 & 6 & 4\\\\7 & -4 & 4\\\\ -6 & 9 & -3\end{bmatrix},\:  \: 9B =9\begin{bmatrix}1 & 5 & -8\\\\ 9 & -5 & -8\\\\ 9 & -5 & 2\end{bmatrix}

  • \rightarrow 3A=\begin{bmatrix} 3*6 & 3*6 & 3*4\\\\3*7 & 3(-4) & 3*4\\\\ 3(-6) & 3*9 & 3(-3)\end{bmatrix},\:\: 9B =\begin{bmatrix}9*1 &9* 5 &9( -8)\\\\ 9*9 & 9(-5) & 9(-8)\\\\ 9*9 & 9(-5) & 9*2\end{bmatrix}

  • \rightarrow 3A=\begin{bmatrix} 18 & 18 & 12 \\\\ 21 & -12 & 12\\\\ -18 & 27 & -9\end{bmatrix},\:\: 9B =\begin{bmatrix} 9 & 45 & -72 \\\\ 81 & -45 & -72\\\\ 81 & -45 & 18\end{bmatrix}

  • \rightarrow 3A+9B=\begin{bmatrix}18+9 & 18+45 & 12+(-72) \\\\ 21+81 & -12 +(-45) & 12+(-72)\\\\ -18+81 & 27+(-45) & -9+18 \end{bmatrix}

  • \rightarrow 3A+9B=\begin{bmatrix} 18+9 & 18+45 & 12-72 \\\\ 21+81 & -12 -45 & 12-72\\\\ -18+81 & 27-45 & -9+18 \end{bmatrix}

  • \rightarrow \purple{\bold{3A+9B=\begin{bmatrix} 27 & 63 & -60 \\\\ 102 & -57 & -60\\\\ 63 & -18 & 9 \end{bmatrix}}}
6 0
2 years ago
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