(ii) 4xz? [- xyz + 3yz?]

The McBrides drove 317 miles on one day and 289 miles on the next day.Estimate the numbet of miles the McBrides drove during the

777dan777 [17]

Just add 317 miles and 289 miles and round

7 0

4 years ago

Residences of U.S. Citizens According to the U.S. Census, 67.5% of the U.S. population were born in their state of residence. In

trasher [3.6K]

Answer:

P(X < 126) = 0.0418

Step-by-step explanation:

To solve this question, we use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

Sample of 203, 67.5% of the U.S. population were born in their state of residence.

This means that $n = 203, p = 0.675$

So, for the approximation:

$\mu = E(X) = np = 203*0.675 = 137.025$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{203*0.675*0.325} = 6.67$

What is the probability that fewer than 126 were born in their state of residence?

Using continuity correction, this is P(X < 126 - 0.5) = P(X < 125.5), which is the pvalue of Z when X = 125.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{125.5 - 137.025}{6.67}$

$Z = -1.73$

$Z = -1.73$ has a pvalue of 0.0418

So

P(X < 126) = 0.0418

8 0

3 years ago

PLEASE help.

Vilka [71]

1 - Not Rent
2 - Not rent
3 - Rent
4 - Rent
5 - I think Not rent?
6- not rent.

5 Can be fixable, because you can just simply not do any of those things. But if that’s not an option I would definitely say not rent

7 0

3 years ago

Evalute the root in the question below in the screenshot<br> (precalc)

hammer [34]

Answer:

Graph attached

Step-by-step explanation:

jenkins-traub method for the complicate calculation

it has 1 real root: 1.5164

2 complex roots : neglected