Answer:
2.29 ft of side length and 1.14 height
Step-by-step explanation:
a) Volume V = x2h, where x is side of square base and h is hite.
Then surface area S = x2 + 4xh because box is open.
b) From V = x2h = 6 we have h = 6/x2.
Substitude in formula for surface area: S = x2 + 4x·6/x2, S = x2 + 24/x.
We get S as function of one variable x. To get minimum we have to find derivative S' = 2x - 24/x2 = 0, from here 2x3 - 24 = 0, x3 = 12, x = (12)1/3 ≅ 2.29 ft.
Then h = 6/(12)2/3 = (12)1/3/2 ≅ 1.14 ft.
To prove that we have minimum let get second derivative: S'' = 2 + 48/x3, S''(121/3) = 2 + 48/12 = 6 > 0.
And because by second derivative test we have minimum: Smin = (12)2/3 + 4(12)1/3(12)1/3/2 = 3(12)2/3 ≅ 15.72 ft2
<span>50x - 32x^3
= 2x (25 - 16x^2)
hope that helps</span>
Answer:
x=11, y=8/3
Step-by-step explanation:
Consider quadrilateral LMNO. If this quadrilateral MUST BE a parallelogram, then
LM=NO
and
LO=MN
Thus,
Solve this system of two equations. From the first equation:
Substitute it into the second equation:
3(x+5)=39
3x+15=39
3x=24
x=8
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