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4vir4ik [10]
2 years ago
7

In a volatile housing market, the overall value of a home can be modeled by V(x) = 415x2 - 4600x + 200000, where V

Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
4 0

Answer:

See below

Step-by-step explanation:

This is a bowl shaped parabola ( due to the positive coefficient of x^2)

   the minimum value (vertex )

      will occur at x value = - b/2a = - -4600/2(415) = 5.54 years

  the minimum VALUE will be the quation with this value of x inserted

 415 (5.54)^2 - 4600(5.54) + 200 000 = $ 187 253.01

The home will reach a minumum value of 187253.01 in 5.54 years

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4.5

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Answer:

Surface area of the cube = 150\ cm^2

Step-by-step explanation:

Given shape in figure 1:

Cube with edge length = 5 cm

To find the surface area of the cube.

Solution:

The surface area of a cube is given by the formula:

Surface\ Area = 6a^2

where a represents the length of the edges of the cube.

For the given cube a=5\ cm

Plugging a=5\ cm in the formula to find the surface area of the cube.

Surface\ Area = 6(5)^2

∴ Surface\ Area = 6\times 25 = 150\ cm^2

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4 years ago
Find the center and radius of the circle represented by the equation below.
valina [46]

Answer:

radius 4

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Step-by-step explanation:

(x - h)^2 + (y - k)^2 = r^2

coordinates of the center (h, k) and the radius is (r)

x² + y²- 6x - 12y +29=0

x² - 6x + y²- 12y +29=0

(x² - 6x) + (y²- 12y) +29=0

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(x-3)^2 + (y-6)^2 = 16

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2 years ago
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I need help I can’t figure it out
dusya [7]

Answer:

\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}

Step-by-step explanation:

\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}

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3 years ago
Hershel is designing a square pyramid that needs to have a lateral surface of 440 in². The area of the base is 121 in². Find the
Snowcat [4.5K]

Answer:

The length of the slant height of the square pyramid is 20 in.

Step-by-step explanation:

The lateral surface area of a regular pyramid is the sum of the areas of its lateral faces.

The general formula for the lateral surface area of a regular pyramid is

                                                     A=\frac{1}{2}pl

where p represents the perimeter of the base and l the slant height.

From the information given we know that:

  • The lateral surface area of a square pyramid is 440 in².
  • The area of the base is 121 in².

And we want to find the the slant height of the pyramid.

For this, we also need to know that the area of a square is given by A=s^2, where <em>s</em> is the length of any side and the perimeter of a square is given by p=4s.

Applying the formula for the area of a square we can find the length of the side

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The perimeter of the base is

p=4\cdot(11)=44

Next, we can apply the formula for the lateral surface area and solve for l the slant height.

440=\frac{1}{2}44l\\\\\frac{1}{2}\cdot \:44l=440\\\\22l=440\\\\l=20

The length of the slant height of the square pyramid is 20 in.

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