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Masteriza [31]
3 years ago
5

Write the fractions from least to greatest. 4/6, 7/12, 5/10

Mathematics
2 answers:
densk [106]3 years ago
7 0
5/10, 7/12, 4/6
Hope this helps!
sammy [17]3 years ago
4 0
The answer would be 5/10, 7/12, and then 4/6
How: What you will do is fine the common denominator between the fractions, which is 60. 
5/10: Multiply numerator and denominator by 6 to get, 30/60. 
7/12: Multiply numerator and denominator by 5 to get, 35/60.
4/6: Multiply numerator and denominator by 10 to get, 40/60.
HOPE THIS HELPS YOU! ^_^
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Read 2 more answers
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leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
3 years ago
Given h(t)=-2(t+5)2 , find h(-8)
amm1812
The answer I got was 12 if needed I can take a picture of how I worked it

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